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3 years ago

Help me please !!! I need this ASAP

Mathematics

1 answer:

Stolb23 [73]3 years ago

8 0

Answer:

the first one

Step-by-step explanation:

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Circle towns limit form a perfectly circular shape that has a population of 20000 in the population density of 480 people per sq

Alex

Answer:

$D =\frac{P}{\pi X^2}$

And solving for the radius we got:

$X = \sqrt{\frac{P}{\pi D}}$

And replacing the data given we got:

$X = \sqrt{\frac{480 \frac{people}{km^2}}{\pi *20000 people}}= 0.0874Km$

And this value converted to meters is $X = 87.40 m$

Step-by-step explanation:

For this case we know the population size $P = 20000$ and we also know the population density $D = 480 \frac{people}{km^2}$

We can assume that the area is a circle. We also know that the formula for the population density is given by:

$D= \frac{P}{A}$

Where P represent the number of people and A the area. Since we are assuming a circle then the area is given by:

$A = \pi X^2$

With X the radius of the circle

And then the populationd density become:

$D =\frac{P}{\pi X^2}$

And solving for the radius we got:

$X = \sqrt{\frac{P}{\pi D}}$

And replacing the data given we got:

$X = \sqrt{\frac{480 \frac{people}{km^2}}{\pi *20000 people}}= 0.0874Km$

And this value converted to meters is $X = 87.40 m$

6 0

4 years ago

Plsss help..............

Alex_Xolod [135]

Prime: 2/8
Even: 6/8
Number 5: 1/8

4 0

3 years ago

Read 2 more answers

A candy manufacturer has 130 pounds of chocolate-covered cherries and 170 pounds of chocolate-covered mints in stock. He decides

Ilia_Sergeevich [38]

Answer:

He should prepare 260 pounds of first mixture and 0 pounds of second mixture

Step-by-step explanation:

Let x be the total quantity ( in pounds ) of cherries and mints in the first mixture and y be the total quantity in second mixture,

Since, first mixture will contain half cherries and half mints by weight,

That is, in first mixture,

Cherries = $\frac{x}{2}$

Mints = $\frac{x}{2}$ ,

While, second mixture will contain one-third cherries and two-thirds mints by weight,

That is, in second mixture,

Cherries = $\frac{y}{3}$

Mints = $\frac{2y}{3}$

According to the question,

The manufacturer has 130 pounds of chocolate-covered cherries and 170 pounds of chocolate-covered mints in stock,

That is,

$\frac{x}{2}+\frac{y}{3} \leq 130$

$\frac{x}{2}+\frac{2y}{3}\leq 170$

Also, pounds can not be negative,

x ≥ 0, y ≥ 0,

Since, the first and second mixture must be sell at the rate of $2.00 per pound and $1.25 per pound respectively,

Hence, the total revenue,

Z = 2.00x + 1.25y

Which is the function that have to maximise,

By plotting the above inequalities,

Vertex of feasible regions are,

(0,255), (180, 120) and (260, 0),

Also, at (260, 0), Z is maximum,

Hence, he should prepare 260 pounds of first mixture and 0 pounds of second mixture in order to maximize his sales revenue.

7 0

3 years ago

Please help been trying for hours

jek_recluse [69]

Answer:

Step-by-step explanation:

i can't see what right there

3 0

3 years ago

I will give Brainiest if you are right

alexira [117]

Answer:

Step-by-step explanation:

G. Plug in x=5 to x-2<7

which becomes

5-2<7

3<7

which is correct.

Hope This Helps!

3 0

3 years ago

Read 2 more answers