Ask question

Ask question

All categories

sergeinik [125]

3 years ago

14

Fine the area of the shape below PLSSS HELP

2 answers:

Rudiy273 years ago

8 0

Answer:

58 yds (squared yards) 6 × 7 = 42, 4 × 4 = 16; 42 + 16 = 58

hope this helps!

erma4kov [3.2K]3 years ago

7 0

Answer:

see how to calculate of this question

You might be interested in

All the fourth-graders in a certain elementary school took a standardized test. A total of 85% of the students were found to be

Aneli [31]

Answer:

There is a 2% probability that the student is proficient in neither reading nor mathematics.

Step-by-step explanation:

We solve this problem building the Venn's diagram of these probabilities.

I am going to say that:

A is the probability that a student is proficient in reading

B is the probability that a student is proficient in mathematics.

C is the probability that a student is proficient in neither reading nor mathematics.

We have that:

$A = a + (A \cap B)$

In which a is the probability that a student is proficient in reading but not mathematics and $A \cap B$ is the probability that a student is proficient in both reading and mathematics.

By the same logic, we have that:

$B = b + (A \cap B)$

Either a student in proficient in at least one of reading or mathematics, or a student is proficient in neither of those. The sum of the probabilities of these events is decimal 1. So

$(A \cup B) + C = 1$

In which

$(A \cup B) = a + b + (A \cap B)$

65% were found to be proficient in both reading and mathematics.

This means that $A \cap B = 0.65$

78% were found to be proficient in mathematics

This means that $B = 0.78$

$B = b + (A \cap B)$

$0.78 = b + 0.65$

$b = 0.13$

85% of the students were found to be proficient in reading

This means that $A = 0.85$

$A = a + (A \cap B)$

$0.85 = a + 0.65$

$a = 0.20$

Proficient in at least one:

$(A \cup B) = a + b + (A \cap B) = 0.20 + 0.13 + 0.65 = 0.98$

What is the probability that the student is proficient in neither reading nor mathematics?

$(A \cup B) + C = 1$

$C = 1 - (A \cup B) = 1 - 0.98 = 0.02$

There is a 2% probability that the student is proficient in neither reading nor mathematics.

6 0

3 years ago

Jeffrey is making a passcode for his new phone. He decides to create a 6

torisob [31]

About 750 different permutations

6 0

3 years ago

Two times the sum of nine and a number is the opposite of 9.

marshall27 [118]

18 that question is confusing so I guessed sorry dude

8 0

3 years ago

I need to be walked through this please.

Aleksandr [31]

Https://us-static.z-dn.net/files/dd1/572d05be5373c1dc9c067ca6690a41a1.jpeg

3 0

4 years ago

Find the values for m and n that would make the following equation true.

dimaraw [331]

You would solve it in two parts.

4*n = 44 Divide by 4

4n/4 = 44/4

n = 11

=============

z^m * z^2 = z^9

When the bases are the same (on the left) the powers on the left add

m + 2

The powers on the left side of the equation are the same as the powers on the right when the bases are the same.

m + 2 = 9 Subtract 2 from both sides.

m + 2 - 2 = 9 - 2

m = 7

=================

Answers

m = 7

n = 11

4 0

3 years ago