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Bas_tet [7]
3 years ago
12

Every 20 seconds a sprinkler passes across a garden will it take more than an hour for the sprinkler to cross the garden 150 tim

es
Mathematics
1 answer:
Ksenya-84 [330]3 years ago
4 0

Answer:

No

Step-by-step explanation:

If the sprinkler takes 20 seconds to cross the garden, and it crosses the garden 150 times, the total number of seconds it took can be calculated by multiplying 20 and 150. You get 3000 seconds, but you need to convert that to minutes to tell if it will take more or less than an hour. So divide 3000 by 60 (the number of seconds in 1 minute). Your answer is 50 minutes. And since 1 hour is 60 minutes, it doesn't take more than an hour to cross the garden 150 times.

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Delilah finds her answer is 90, but she copied the expression incorrectly from the board. If her reasoning and answer for the ex
USPshnik [31]

Question:

Three students were working on 630,000÷700 in math class.

a. Desiree finds the quotient is 9,000 and Micah finds the quotient is 900.

    Determine which student found the correct quotient.

b. Delilah finds her answer is 90, but she copied the expression incorrectly from the board. If her reasoning and answer for the expression she copied are correct, what expression might she have written?

Answer:

a. Micah is correct

b.

Expression = 63000 \div 700

Expression = 630000 \div 7000

Step-by-step explanation:

Given

Expression = 630000 \div 700

Desiree = 9000

Micah = 900

Solving (a): Who is correct?

To do this, we first calculate the quotient of the expression.

Expression = 630000 \div 700

Divide 630000 by 700

Quotient = 900

Hence:

Micah is correct

Solving (b): What Delilah must have copied?

We have:

Delilah = 90

There are no options to pick from. So, we just need to work out expressions that equals 0.

Possible expressions are:

Expression = 63000 \div 700

Expression = 630000 \div 7000

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3 years ago
Help me with this problem?
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A prospective mother and a prospective father are hemophiliacs. (Enter your answers as fractions.)
Katena32 [7]

So remember that Hemophilia is <u>a recessive, x linked trait.</u>

For a woman to have hemophilia, she must have the trait linked to both x chromosomes. For a man to have hemophilia, he must have the trait linked to his singular x chromosome.

For this, I will be making a Punnett Square to determine the Possibilities:

\left[\begin{array}{cccc}&&X_h&Y\\&&-&-\\X_h&|&X_hX_h&X_hY\\X_h&|&X_hX_h&X_hY\end{array}\right]

<h3>A.</h3>

Since there is a 1/2 chance for their offspring to be a boy, and of that 1/2 both would be hemophiliacs, <u>there is a 1/2 chance for the child to be a hemophiliac male.</u>

<h3>B.</h3>

As previously mentioned, for a woman to have hemophilia, they would need to have that trait attached to both x chromosomes. Since there is a 1/2 chance for their offspring to be a girl, and of that 1/2 both would be hemophiliacs (since they both carry the trait on both chromosomes), <u>there is a 1/2 chance that they will have a hemophiliac female.</u>

<h3>C.</h3>

<u>So a carrier is someone who carries a recessive trait, but it isn't displayed due to the dominant trait masking it. With x-linked traits, only women can be carriers since they carry more than one x chromosome.</u> What this asks is the probability of an offspring having the trait attached to only 1 of the x chromosomes. Looking at the girls, since both carry the traits on both x chromosomes, <u>there is 0 chance of a carrier.</u>

<h3>D.</h3>

So symptom free is as it seems, without the hemophilia trait. Looking at the table, since all the offspring contain the hemophilia trait, <u>there is 0 chance that any of their offspring will go symptom free.</u>

7 0
3 years ago
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