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Sever21 [200]
3 years ago
8

Subtract (4x-3y) from the sun of (12x+9y) and (-2y)

Mathematics
1 answer:
Svetlanka [38]3 years ago
6 0

to begin with, we have to add 12x+9y+-2y we add like terms(y and y)

12x+7y

next, we have to subtract 4x-3y from 12x+9y

(12x+9y)-(4x-3y)

our answer is: 8x+12y

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kate spent 3/5 of her money on a manicure and had $45 left. how much money did she have at first?(PLEASE SHOW STEPS!)
prisoha [69]
Lets say she has x money

Now she spent 3/5of x means 2/5 is left
2/5*x=45
x=112.5
7 0
3 years ago
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What is the surface area of the cylinder with height 4 m and radius 2 m? Round your answer to the nearest thousandth. ​
Tems11 [23]

Answer:

<h2>          75.398 m²</h2>

Step-by-step explanation:

A=2\cdot\pi R^2+ 2\pi R\cdot H\\\\H=4\,m\\R=2\,m\\\\A=2\cdot\pi\cdot 2^2+2\pi \cdot2\cdot4=8\pi+16\pi=24\pi=75.398223....\approx75.398\ m^2

5 0
3 years ago
-27=-3p+15-3p solve the equation and show your work
Gnesinka [82]
-27 = -3p + 15 - 3p

Combine like terms.
-3p -3p = (-3-3)p = -6p

-27 = -6p + 15

Subtract 15 from each side to get the variable term on its own.

-27 - 15 = -6p + 15 - 15

-42 = -6p

Divide each side by -6 to find p.

p = -42 ÷ -6 = 7
6 0
3 years ago
-2a<br> 0b<br> -2<br> × -5b<br> 4<br> × -b
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Answer:

Step-by-step explanation:

Army DA administrative publications and forms by the Army Publishing Directorate APD. The latest technologies high quality electronic pubs and forms view ...

8 0
3 years ago
The doubling period of a bacterial population is 15 minutes. At time t= 80 minutes, the bacterial population was 90000​
Papessa [141]

Answer:

here i finished!

hope it helps yw!

Step-by-step explanation:

The doubling period of a bacterial population is 15 minutes.

At time t = 90 minutes, the bacterial population was 50000.

Round your answers to at least 1 decimal place.

:

We can use the formula:

A = Ao*2^(t/d); where:

A = amt after t time

Ao = initial amt (t=0)

t = time period in question

d = doubling time of substance

In our problem

d = 15 min

t = 90 min

A = 50000

What was the initial population at time t = 0

Ao * 2^(90/15) = 50000

Ao * 2^6 = 50000

We know 2^6 = 64

64(Ao) = 50000

Ao = 50000/64

Ao = 781.25 is the initial population

:

Find the size of the bacterial population after 4 hours

Change 4 hr to 240 min

A = 781.25 * 2^(240/15

A = 781.25 * 2^16

A= 781.25 * 65536

A = 51,199,218.75 after 4 hrs

6 0
3 years ago
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