U would measure it with the teaspoon and the 1/6 teaspoon
you would need 2 use the 1/2 teaspoon 4 times to get 2 teaspoons and the `1/6 teaspoon 4 times to get 2/3.
1/6+1/6=2/6*2=4/6 =2/3
hope this helps
Answer:
c, 85°
Step-by-step explanation:
95° + xz = 180° then
x = 180 ° - 95° = 85°
Let h be height of building
then In ΔABC
AB/BC =tan60degree
h/100 = root 3
h= 100 root 3
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Jessi work is correct. Everyone did the work correctly as far as the method but only Jessi’s work was correct because 6/12 = 1/2
YOUR ANNSWER IS B OR JESSI’S WORK.
Using the normal distribution, there is a 0.2076 = 20.76% probability that the proportion of persons with a college degree will differ from the population proportion by greater than 3%.
<h3>Normal Probability Distribution</h3>
The z-score of a measure X of a normally distributed variable with mean
and standard deviation
is given by:

- The z-score measures how many standard deviations the measure is above or below the mean.
- Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.
- By the Central Limit Theorem, for a proportion p in a sample of size n, the sampling distribution of sample proportion is approximately normal with mean
and standard deviation
, as long as
and
.
The proportion estimate and the sample size are given as follows:
p = 0.45, n = 437.
Hence the mean and the standard error are:
The probability that the proportion of persons with a college degree will differ from the population proportion by greater than 3% is <u>2 multiplied by the p-value of Z when X = 0.45 - 0.03 = 0.42</u>.
Hence:

By the Central Limit Theorem:

Z = (0.42 - 0.45)/0.0238
Z = -1.26
Z = -1.26 has a p-value of 0.1038.
2 x 0.1038 = 0.2076.
0.2076 = 20.76% probability that the proportion of persons with a college degree will differ from the population proportion by greater than 3%.
More can be learned about the normal distribution at brainly.com/question/28159597
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