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jolli1 [7]
3 years ago
12

Triangles ABC and DEF are similar find the length of segment DF​

Mathematics
1 answer:
asambeis [7]3 years ago
8 0

Answer:

2.68

Step-by-step explanation:

In similar triangles, the corresponding sides are in same ratio

\frac{DF}{AC} =\frac{DE}{AB}\\\\\frac{DF}{4} = \frac{1.34}{2}\\\\ DF = \frac{1.34}{2}*4\\\\DF = 1.34 * 2 \\\\DF = 2.68

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If a basket of goods and services used to calculate CPI contains 2 pairs of socks at $2 each and 1 pair of shoes at $50, what wi
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Answer:

B. 55.10

Step-by-step explanation:

Given:

1 pair of Shoes for 1st year = $50

2 pair of Sock for 1st year = $2 each = 2\times2= $4

\therefore CPI for year 1 = Price of shoes for 1st year + Price of Sock for 1st year= $50 + $4 = $54

Now

1 pair of Shoes for 2nd year = $51

2 pair of Sock for 2nd year = $2.05 each = 2 \times2.05 =$4.10

\therefore CPI for Year 2 = Price of shoes for 2nd year + Price of Sock for 2nd year= $51 + $4.1 = $55.10

Hence CPI for Year 2 is $55.10

7 0
3 years ago
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Answer:

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Step-by-step explanation:

5 0
3 years ago
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Is 3+(−4) the same as −4+3? Explain. 3+(−4) the same as −4+3 because of the Property of Addition.
stiks02 [169]

Answer:  The − sign here means subtraction. However, recall that 4 − 7 can be rewritten as 4 + (−7), since subtracting a number is the same as adding its opposite.

Step-by-step explanation:

6 0
2 years ago
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Meghan's dog spray eats 4 ¹/4 cups of food each day. Explain how megan can determine how much food to give sparky if she needs t
Alexxandr [17]

Answer:

\frac{17}{6}\ cups

Step-by-step explanation:

Total\ required\ food\ for\ sparky=4\frac{1}{4}\ cups\\\\Total\ required\ food\ for\ sparky=\frac{17}{4}\ cups\\\\Megan\ needs\ to\ feed\ him\ only\ \frac{2}{3}\ as\ much\\\\Food\ given\ by\ Megan=\frac{2}{3}\times Total\ required\ food\ for\ sparky\\\\Food\ given\ by\ Megan=\frac{2}{3}\times \frac{17}{4}\\\\Food\ given\ by\ Megan=\frac{17}{6}\ cups

6 0
4 years ago
The spherical balloon is inflated at the rate of 10 m³/sec. Find the rate at which the surface area is increasing when the radiu
rjkz [21]

The balloon has a volume V dependent on its radius r:

V(r)=\dfrac43\pi r^3

Differentiating with respect to time t gives

\dfrac{\mathrm dV}{\mathrm dt}=4\pi r^2\dfrac{\mathrm dr}{\mathrm dt}

If the volume is increasing at a rate of 10 cubic m/s, then at the moment the radius is 3 m, it is increasing at a rate of

10\dfrac{\mathrm m^3}{\mathrm s}=4\pi (3\,\mathrm m)^2\dfrac{\mathrm dr}{\mathrm dt}\implies\dfrac{\mathrm dr}{\mathrm dt}=\dfrac5{18\pi}\dfrac{\rm m}{\rm s}

The surface area of the balloon is

S(r)=4\pi r^2

and differentiating gives

\dfrac{\mathrm dS}{\mathrm dt}=8\pi r\dfrac{\mathrm dr}{\mathrm dt}

so that at the moment the radius is 3 m, its area is increasing at a rate of

\dfrac{\mathrm dS}{\mathrm dt}=8\pi(3\,\mathrm m)\left(\dfrac5{18\pi}\dfrac{\rm m}{\rm s}\right)=\dfrac{20}3\dfrac{\mathrm m^2}{\rm s}

4 0
3 years ago
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