Answer:
I think it would be Federal student loans if I am sure sorry if you get it wrong.
Explanation:
I think the answer is C but I could be wrong
Virtual memory could be used to allow program 5 to access RAM without any of the data from the other four programs being lost because it is one that tend to allows the system to give all of the process its own memory space that is said to be isolated from the other processes.
<h3>How is virtual memory used instead of RAM?</h3>
A system is known to make use of a virtual memory and this is one that tend to make use of a section of the hard drive to act like the RAM.
With the use of virtual memory, a system can be able to load bigger or a lot of programs running at the same time, and this is one that tends to hep one to work as if it has more space, without having to buy more RAM.
Therefore, Virtual memory could be used to allow program 5 to access RAM without any of the data from the other four programs being lost because it is one that tend to allows the system to give all of the process its own memory space that is said to be isolated from the other processes.
Learn more about virtual memory from
brainly.com/question/13088640
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Answer:
import java.util.Scanner;
public class Main
{
public static void main(String[] args) {
Scanner in = new Scanner(System.in);
System.out.println("Enter the number of bottles and cans:");
int numberOfbottles = in.nextInt();
int numberOfcans = in.nextInt();
System.out.printf("Bottles: %8d\n", numberOfbottles);
System.out.printf("Cans: %8d\n", numberOfcans);
}
}
Explanation:
Ask user to input the number of bottles and cans using Scanner class
Print the results so that the numbers to the right line up (Since we know that the numbers have at most 8 digits, we can use %8d in printf. Also, be aware that how printf statements are written so that the numbers line up)
Answer:
Explanation:
The following code is written in Python and is a recursive function as requested that uses the current value of p (which is count in this instance) and raises 2 to the power of p. If the result is greater than or equal to the value of n then it returns the value of p (count) otherwise it raises it by 1 and calls the function again.
def next_pow2(n, count = 0):
if (2**count) < n:
count += 1
return next_pow2(n, count)
else:
return count
