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Hatshy [7]
3 years ago
11

Which one of the following is a benefit of using a contact group?

Computers and Technology
1 answer:
lisov135 [29]3 years ago
6 0

Answer:

There are some benefit of using a contact group.

Explanation:

An email address collection consists of a contact group (formerly known as a "distribution list."). You can send an E-mail or invitation to meet to all addresses at the same time by using a contact group. In the messages, task requests, requests for meetings, and other contact groups you can include contact groups. Another advantage of contact groups is that they categorize your contacts so that a particular person can be found more easily in future. Depending on how far you want to reach with your contact organization, you can contact one group or more groups

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Which of the following is an object-oriented programming language?
Svetradugi [14.3K]

Explanation:

This is the correct answer

<h3>python</h3>
7 0
2 years ago
Which of the following is an example of how cookies are used? To create a stronger password To customize advertisements based on
fiasKO [112]

The one among the options that is an example of how cookies are used to customize advertisements based on your history.

<h3>What do cookies do?</h3>

A cookie is known to be a kind of a small text file that is said to be often saved on your computer if a person do visit any kind of websites.

Note also that  a cookie is often used to get one to often remember settings that they have their last visit to any website.

For example Amazon is known to often cookies to help to know if or when a person revisit the site.

Hence, The one among the options that is an example of how cookies are used to customize advertisements based on your history.

Learn more about cookies from

brainly.com/question/14102192

#SPJ1

8 0
2 years ago
Design a program takes as input, X, an unsorted list of numbers, and returns the sorted list of numbers in X. The program must b
Lelechka [254]

Answer:

The program in python is as follows:

def split(X):

   L = []; G = []

   for i in range(len(X)):

       if X[i]>=X[0]:

           G.append(X[i])

       else:

           L.append(X[i])

   L.sort(); G.sort()

   return L,G

X = []

n = int(input("Length of X: "))

for i in range(n):

   inp = int(input(": "))

   X.append(inp)

   

if len(X) == 0 or len(X) == 1:

   print(X)

else:

   X1,X2=split(X)

   newList = sorted(X1 + X2)

   print(newList)

Explanation:

The following represents the split function in the previous problem

def split(X):

This initializes L and G to empty lists

   L = []; G = []

This iterates through X

   for i in range(len(X)):

All elements of X greater than 0 equal to the first element are appended to G

      <em> if X[i]>=X[0]:</em>

<em>            G.append(X[i])</em>

Others are appended to L

<em>        else:</em>

<em>            L.append(X[i])</em>

This sorts L and G

   L.sort(); G.sort()

This returns sorted lists L and G

   return L,G

The main function begins here

This initializes X

X = []

This gets the length of list X

n = int(input("Length of X: "))

This gets input for list X

<em>for i in range(n):</em>

<em>    inp = int(input(": "))</em>

<em>    X.append(inp)</em>

This prints X is X is empty of has 1 element

<em>if len(X) == 0 or len(X) == 1:</em>

<em>    print(X)</em>

If otherwise

else:

This calls the split function to split X into 2

   X1,X2=split(X)

This merges the two lists returned (sorted)

   newList = sorted(X1 + X2)

This prints the new list

   print(newList)

7 0
3 years ago
This function searches for the first occurence of a string inside another string.
emmainna [20.7K]

Answer:

strchr()

Explanation:

Among the following options strchr() is the sring function that used to search for the  first occurence of a string inside  another string.

strlen() function is used to find the length of the string.

strcmp() is used to compare two strings and returns either 0 or 1.

strcasecomp() this function is used to compare the case of characters of two strings.

3 0
3 years ago
Write an application for a lawn-mowing service. The lawn-mowing season lasts for 20 weeks. The weekly fee for mowing a lot less
jenyasd209 [6]

Answer:

// library

import java.util.*;

// class definition

class Main

{// main method of the class

public static void main (String[] args) throws java.lang.Exception

{

   try{

    // object to read inputs

      Scanner scr=new Scanner(System.in);

      System.out.print("Enter length of lawn:");

      // read the length of lawn

      int length=scr.nextInt();

      System.out.print("Enter width of lawn:");

      // read the width of lawn

      int width=scr.nextInt();

      // find area of lawn

      int area=length*width;

      //if area is less than 400

      if(area<400)

      {// Weekly mowing fee

          System.out.println("Weekly mowing fee is:$25");

          // seasonal fee

          System.out.println("20-week seasonal fee is:$"+(25*20));

      }

      // if area >=400 and area <600

      else if(area>=400 && area<600)

      {

         // Weekly mowing fee

          System.out.println("Weekly mowing fee is:$35");

          // seasonal fee

          System.out.println("20-week seasonal fee is:$"+(35*20));

      }

      // if area >=600

      else if(area>=600)

      {

         // Weekly mowing fee

          System.out.println("Weekly mowing fee is:$50");

          // seasonal fee

          System.out.println("20-week seasonal fee is:$"+(50*20));

      }

   }catch(Exception ex){

       return;}

}

}

Explanation:

Read the length and width of lawn from user with the help of scanner object. Find the area of the lawn.If the area if less than 400 then Weekly mowing fee  is $25 and find the 20-week seasonal fee by multiply 25 with 20.If the area is greater than 400 and less than 600 then Weekly fee is $35 and seasonal fee  will be 35*20.if the area is greater than 600 then Weekly fee is $50 and seasonal fee will be 50*20.

Output:

Enter length of lawn:15                                                                                                    

Enter width of lawn:12                                                                                                    

Weekly mowing fee is:$25                                                                                                  

20-week seasonal fee is:$500

4 0
4 years ago
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