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3 years ago

2(10.8 k+ 2.9) What's the answer

Mathematics

1 answer:

motikmotik3 years ago

3 0

21.6k + 11.8

I believe is the answer good luck!

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Helppppppppppp plsssssss n ty

Alexus [3.1K]

Answer:

C. $\frac{1}{8}$

C. $\frac{1}{32}$

Step-by-step explanation:

A unit fraction is a fraction that has 1 as it's numerator and a positive number as it's denominator.

5 0

2 years ago

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What is the absolute value of 6.75?

dusya [7]

6.75 is the absolute value of 6.75 absolute value is distance from zero and 6.75 is 6.75 from 0 so is -6.75

6 0

3 years ago

Read 2 more answers

I’ll give brainliest!!!

n200080 [17]

Answer:

A) arithmetic sequence

g(n) = 20 + 3n

Step-by-step explanation:

Each minute, the number of pages increases by 3, which means the common difference is 3 (because it is being added, not multiplied).

If there is a common difference, it's an arithmetic sequence. (Geometric sequences have common ratios.)

If she starts at 20 pages, then you just need to multiply 3 by the number of minutes passed (n) and add it to 20 to find the page she's on.

5 0

3 years ago

Jacy has a collection of 140 coins worth $19.00. She has only nickels, dimes, and quarters. The difference in the

Colt1911 [192]

Answer:50(b)

Step-by-step explanation:

I just took the test

7 0

3 years ago

An assembly consists of two mechanical components. Suppose that the probabilities that the first and second components meet spec

harkovskaia [24]

Answer:

P(X = 0) = 0.0208, P(X = 1) = 0.2484, P(X = 2) = 0.7308

Step-by-step explanation:

Let's define the following events

A: the first component meet specification

B: the second component meet specification

P(A) = 0.87

P(B) = 0.84

Let X be the random variable that represents the number of components in the assembly that meet specifications. Because there are only two mechanical components in the assembly, X can only take the values 0, 1, 2.

P(X = 0) = P(the first component does not meet specification and the second component does not meet specification) =

$P(A^{c}\cap B^{c}) = P(A^{c})P(B^{c})$ (because of independence)

= (0.13)(0.16) = 0.0208

P(X = 1) = P(only one component meet specification) = P[(the first component meet specification and the second component does not meet specification) or (the first component does not meet specification and the second component meet specification)] =

$P[(A\cap B^{c})\cup (A^{c}\cap B)] = P(A\cap B^{c}) + P(A^{c}\cap B)=$ (because sets are mutually exclusive)

$P(A)P(B^{c}) + P(A^{c})P(B)=$ (because of independence)

= (0.87)(0.16) + (0.13)(0.84) = 0.2484

P(X = 2) = P(both components meet specifications) =

$P(A\cap B) = P(A)P(B)$ (because of independence)

= (0.87)(0.84)

= 0.7308

8 0

3 years ago