Answer:
x+3y-6=0
Step-by-step explanation:
given eqn is y=3x-2 which is 3x-y-2=0
the eqn of line perpendicular to given eqn is -x+3y+k=0
it passes through (6,4)
-6+3*4+k=0
or,. -6+12+k=0
or, k= -6
therefore, the eqn of line perpendicular to given eqn is x+3y-6=0
Final Answer: 
Steps/Equations:
Question: 
Step 1: Move the negative sign to the left side.

Step 2: Multiply both sides by
.

Step 3: Simplify
to
.

Step 4: Multiply both sides by
.

~I hope I helped :)~
3,2,1,6 are all factors of 6.
7.5%
how to do it
to dived 600 m by 8000m and get .075 to switch it to % you multiply it by 100 geting 7.5%