please help! i'll mark brainliest if correct! Use the second image attached to answer the question! HELP ASAP

The area of a square is 8 square meters. which of these is closest to the length of one side of the square?''

sveticcg [70]

I hope this helps you

3 0

2 years ago

Read 2 more answers

The length of a rectangle is 8 inches longer than the width. If the area is 295 square inches, find the

sladkih [1.3K]

Answer:

L=21.6in and w=13.6

Step-by-step explanation:

If the length is 8 inches longer than its width, we can write the width as "w" and the length as the width w+ 8

Area is (width)(Length) = (width)(width+8)

W

----------

| |

| | L = w+8

| |

-----------

A = (w+8)(w)

A = w2 + 8w = 295.

(Problem states that area is 295 sq in)

Need to solve this quadratic equation

w2 +8y - 295 = 0

Factor:

(w - 13.64) (w + 21.64) = 0

So

w - 13.64 = 0. or. w + 21.64= 0

Solve these and get

w = 13.64. or. w = -21.64

Only one that makes sense in real life is the poitive one.

So the dimensions are

Width = 13.64 inches

Length = 21.64 inches

7 0

2 years ago

Members of the drama club spend $795 on t-shirts and sweatshirts for a play.They purchase 20 more tshirts than sweatshirts.They

Anika [276]

Answer:

The drama club bought 35 t-shirt

Step-by-step explanation:

Let

t-shirt = x

Sweatshirt = y

Total cost = $795

They purchase 20 more tshirts than sweatshirts

x = y + 20

The equation is:

12x + 25y = 795

12(y + 20) + 25y = 795

12y + 240 + 25y = 795

37y = 795 - 240

37y = 555

y = 15

Substitute y = 15 into

x = y + 20

x = 15 + 20

x = 35

t-shirt = 35

Sweatshirt = 15

The drama club bought 35 t-shirt

8 0

2 years ago

Derivative of<br><img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B%20%7B3x%7D%5E%7B2%7D%20-%202x%20-%201%20%7D%7B%20%7Bx%7D%5E%7B2

Anastaziya [24]

Answer:

$\displaystyle \frac{dy}{dx} = \frac{2x + 2}{x^3}$

Step-by-step explanation:

we would like to figure out the derivative of the following:

$\displaystyle \frac{ { 3x }^{2} - 2x - 1 }{ {x}^{2} }$

to do so, let,

$\displaystyle y = \frac{ { 3x }^{2} - 2x - 1 }{ {x}^{2} }$

By simplifying we acquire:

$\displaystyle y = 3 - \frac{2}{x} - \frac{1}{ {x}^{2} }$

use law of exponent which yields:

$\displaystyle y = 3 - 2 {x}^{ - 1} - { {x}^{ - 2} }$

take derivative in both sides:

$\displaystyle \frac{dy}{dx} = \frac{d}{dx} (3 - 2 {x}^{ - 1} - { {x}^{ - 2} } )$

use sum derivation rule which yields:

$\rm\displaystyle \frac{dy}{dx} = \frac{d}{dx} 3 - \frac{d}{dx} 2 {x}^{ - 1} - \frac{d}{dx} {x}^{ - 2}$

By constant derivation we acquire:

$\rm\displaystyle \frac{dy}{dx} = 0 - \frac{d}{dx} 2 {x}^{ - 1} - \frac{d}{dx} {x}^{ - 2}$

use exponent rule of derivation which yields:

$\rm\displaystyle \frac{dy}{dx} = 0 - ( - 2 {x}^{ - 1 -1} ) - ( - 2 {x}^{ - 2 - 1} )$

simplify exponent:

$\rm\displaystyle \frac{dy}{dx} = 0 - ( - 2 {x}^{ -2} ) - ( - 2 {x}^{ - 3} )$

two negatives make positive so,

$\displaystyle \frac{dy}{dx} = 2 {x}^{ -2} + 2 {x}^{ - 3}$

<h3>further simplification if needed:</h3>

by law of exponent we acquire:

$\displaystyle \frac{dy}{dx} = \frac{2 }{x^2}+ \frac{2}{x^3}$

simplify addition:

$\displaystyle \frac{dy}{dx} = \frac{2x + 2}{x^3}$

and we are done!

5 0

2 years ago

Took a photo to use

ruslelena [56]

Answer:

x=9

<A=23

<B= 69

Step-by-step explanation:

1. 2x+5+3(2x+5)=92 2. 2x+5+6x+15=92 3. 8x+20=92 4. 8x=72 5. x=9

<A= 2(9)+5=18+5=23

<B= 3(2(9)+5)=3(23)=69

5 0

2 years ago