x + y = 3.36 --> the boys are splitting $3.36
x = 3y - .12 --> one boy received $.12 less than 3 times as much as the other
--> substitute the second equation for the x in the first equation
(3y - .12) + y = 3.36 --> combine like terms
4y - .12 = 3.36 --> add .12 to both sides of the equation
4y = 3.48 --> divide both sides by 4
y = .87
the other boy gets $0.87
substitute into x = 3y - 12
x = 3(.87) - .12
x = 2.61 - .12
x = 2.49
the first boy gets $2.49
Hello there!
Domain={-3,5,2}
Range={6,3,1}
Hope this helps
Have a great day/night
Answer:
3 cups
Step-by-step explanation:
we can solve this by setting up ratios
cross multiply:
solve for x
Solution:
Let's verify each option to see which is correct.
<u>Option A</u>
Two subtracted from the quotient of seven divided by b.
- => 7/b - 2 = 7(b - 2) [False]
<u>Option B</u>
Seven added to difference of b minus two.
- => 7 + (b - 2) = 7(b - 2) [False]
<u>Option C</u>
The quotient of seven divided by b minus two.
- => 7/b - 2 = 7(b - 2) [False]
<u>Option D</u>
Two subtracted from seven times b
- => 7b - 2 = 7(b - 2) [False]
<u>Option E</u>
The product of seven and the difference of b minus two
- => 7 x (b - 2) = 7(b - 2) = 7(b - 2) [True]
Option E is correct.
20^2 + (x-8)^2 = x^2
x^2 = 400 + x^2 -16x + 64
16x = 464
x = 29 = hypotenuse
Double - Check
29^2 = 20^2 + 21^2
841 = 400 + 441
