Assume a is not divisible by 10. (otherwise the problem is trivial).
<span>Define R(m) to be the remainder of a^m when divided by 10. </span>
<span>R can take on one of 9 possible values, namely, 1,2,...,9. </span>
<span>Now, consider R(1),R(2),......R(10). At least 2 of them must have the sames value (by the Pigeonhole Principle), say R(i) = R(j) ( j>i ) </span>
<span>Then, a^j - a^i is divisible by 10.</span>
What you do here is subtract g from f: x^2 - 5x + 8 - (x^2 -4); x^2 - 5x + 8 - x^2 + 4; Rearranging gives you x^2 - x^2 - 5x + 8 + 4 which is, simplified, -5x + 12
80.75 / 8.50 = 9.5
Sean worked 9 and a half hours.
10.2 ft Ans.
We solve this using geometric series.
A1 = 12 ft
A2 = ?
A3 = 8.67ft
Now, for geomteric progression,
![\frac{A1}{A2} = \frac{A2}{A3} ](https://tex.z-dn.net/?f=%20%5Cfrac%7BA1%7D%7BA2%7D%20%3D%20%20%5Cfrac%7BA2%7D%7BA3%7D%20%0A%0A%20%20)
![\frac{12}{A2} = \frac{A2}{8.67}](https://tex.z-dn.net/?f=%20%5Cfrac%7B12%7D%7BA2%7D%20%3D%20%5Cfrac%7BA2%7D%7B8.67%7D%20)
A2 = 10.2 ft
Answer:
b because first u need to remove the parentheses then u disturbe