Answer:
Step-by-step explanation:
since they are both equal to 'y', you can eliminate the y but letting the value of y equal to each other
if they are not both equal to 'y', then solve the equation by putting y itself on 1 side
1. sub y=-2x into 2nd equation
-2x = 3x + 25
then solve for x
-5x = 25
x= -5
2.
y-2 =12x
y = 12x +2
(sub this equation into y=x+2)
12x + 2 = x + 2
11x = 4
x = 4/11
hope this makes sense, please let me know if it doesn't and i'll help out some more
i'm not that great at explaining, sorry
Answer:
x>-2
Step-by-step explanation:
-9x-15<3
+15<+15 add 15 to both sides
_________
-9x<18
÷-9 <÷-9 divide both sides by -9, switch inequality _________ symbol when dividing by negative number.
x>-2 Answer
_________
Answer:50.18
Step-by-step explanation:
8x+17+9x+11=102
17x+28=102
-28. -28
17x=74
<CAD=9x+11=50.18
x=74/17
Step-by-step explanation:
On each side of this quadrilateral, you have supplementary angles, in other wourds, angles that sum up to <em>one hundred eighty degrees</em>:
![\displaystyle 180° = [3y + 14]° + [10y - 29]° \\ 180° = [-15 + 13y]° \\ \frac{195}{13} = \frac{13y}{13} \\ \\ 15 = y; 59° = [3(15) + 14]° \\ \\ \\ \\ 180° = [5x - 2]° + [x + 14]° \\ 180° = [12 + 6x]° \\ \frac{168}{6} = \frac{6x}{6} \\ \\ 28 = x; 138° = [5(28) - 2]°](https://tex.z-dn.net/?f=%5Cdisplaystyle%20180%C2%B0%20%3D%20%5B3y%20%2B%2014%5D%C2%B0%20%2B%20%5B10y%20-%2029%5D%C2%B0%20%5C%5C%20180%C2%B0%20%3D%20%5B-15%20%2B%2013y%5D%C2%B0%20%5C%5C%20%5Cfrac%7B195%7D%7B13%7D%20%3D%20%5Cfrac%7B13y%7D%7B13%7D%20%5C%5C%20%5C%5C%2015%20%3D%20y%3B%2059%C2%B0%20%3D%20%5B3%2815%29%20%2B%2014%5D%C2%B0%20%5C%5C%20%5C%5C%20%5C%5C%20%5C%5C%20180%C2%B0%20%3D%20%5B5x%20-%202%5D%C2%B0%20%2B%20%5Bx%20%2B%2014%5D%C2%B0%20%5C%5C%20180%C2%B0%20%3D%20%5B12%20%2B%206x%5D%C2%B0%20%5C%5C%20%5Cfrac%7B168%7D%7B6%7D%20%3D%20%5Cfrac%7B6x%7D%7B6%7D%20%5C%5C%20%5C%5C%2028%20%3D%20x%3B%20138%C2%B0%20%3D%20%5B5%2828%29%20-%202%5D%C2%B0)
I am joyous to assist you at any time.
Answer:
y=30
Step-by-step explanation:
this fits into the negative association if you plotted the point (80,30) it would fit into the graph and not stand out in either direction
