Question

Identify the equation of the circle B that passes through (4, -6) and has center (3, -2).

Answer 1

Answer:

solution given :

centre (h,k)=(3,-2)

another point (a,b)=(4,-6)

now

radius =$\sqrt{(3-4)²+(-2+6)²}$=√17

We have

equation of a circle is:

(x-h)²+(y-k)²=r²

(x-4)²+(y+6)²=17 is a required equation.