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Dmitrij [34]
2 years ago
9

You are planning to put a new digital flat t.v on a wall that is 12ft long and 9ft high. the digital t.v has a diagonal of 72 in

ches. the length of the t.v. is twice the width of the tv how much of the wall will still need to be decorated around the tv?
Mathematics
1 answer:
Pie2 years ago
7 0
Area of wall = 9 * 12 = 108 ft^2
Width of TV = x
Lenght = 2x
Diagonal of TV = 72 " = 6 ft


x^2+(2x)^2=6^2
x^2+4x^2=36
5x^2=35
x^2=36/5
x=sqrt(36/5)
Width = 2.68 ft.
Length = 2.68 * 5.36 = 14.36 ft^2
Area of wall - area of tv = 108 - 14.36 = 93.64 ft

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Can someone help me with this question please.
galina1969 [7]

Answer:

6, 8, and 10.

Step-by-step explanation:

You could work this out with the pythagorean theorem, by proving that 6^2, 36, plus 8^2, 64, equals 100. The fastest way, however, is to use pythagorean triples. These are predetermined sets of numbers that work as side lengths for right triangles. The first two are 3, 4, and 5, which form a right triangle, and 6, 8, and 10, shown here.

5 0
2 years ago
The dot plots below show the scores for a group of students for two rounds of a quiz: Two dot plots are shown one below the othe
miskamm [114]

Answer:

The inference that can be made using the dot plot is:

    The range of round 1 is greater than the round 2 range.

Step-by-step explanation:

<u>Round 1:</u>

Score                Frequency

  1                          0

  2                          2

  3                          3

  4                          2  

  5                          1

Hence, the minimum score of Round 1 is: 2

maximum score is: 5

Hence, Range=Maximum value-Minimum score

                      =5-2

                       =3

Similarly, <u>Round-2</u>

Score                Frequency

  1                          0

  2                         0

  3                          0

  4                          4  

  5                          4

Hence, the minimum score of Round 1 is: 4

maximum score is: 5

Hence, Range=Maximum value-Minimum score

                      =5-4

                       =1

The scores of round 2 are higher than round-1.

Since round 2 have a higher frequency for higher scores as compared to round-1.

Hence, Range of round 1 is greater than the range of Round-2.

 

6 0
2 years ago
Read 2 more answers
What is the answer to this equation “A = ?”<br><br> G(a + h) = M
sasho [114]

Answer:

a  = M -Gh/G

Step-by-step explanation:

in order to make a the subject of fomular , you will open the bracket first and then combine the like terms.

G(a + h) = M

Ga + Gh  = M

Ga = M - Gh

since G is disturbing a from standing alone, we divide both sides by G

Ga/G = M- Gh/ G

a  = M -Gh/G

7 0
3 years ago
Probability!
Reil [10]

Answer:

26/31

Step-by-step explanation:

N(B)=12

N(G)=14

N(Y)=5

N(S)=N(B)+N(G)+N(Y)

=12+14+5

=31

Now,

P(Not getting yellow)=N(B)+N(G)/N(S)

=12+14/31

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2 years ago
Find the area of the given figure.
marissa [1.9K]

84.6 km2 is the answer

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3 years ago
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