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3 years ago

Please, Help please!

Mathematics

1 answer:

svp [43]3 years ago

6 0

It will take jeremy 48 minutes

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From an airplane flying over the ocean, the angle of depression to a submarine lying under the surface if 24 degrees 10 minutes.

forsale [732]

I think is 10 m/ s per sec

4 0

3 years ago

Please help with this question

lions [1.4K]

Answer:

sin( -∅ )

- 1 / csc ( ∅ )

1 / csc ( -∅ )

Step-by-step explanation:

Since sin(x) is and odd function (a function where f(-a) = f(a) ).

-sin( ∅ ) = sin( -∅ )

On the other hand, we know that sin( ∅ ) = 1 / csc ( ∅ )

Another odd function, so the same as before applies.

-sin( ∅ ) = -1 / csc ( ∅ )

-sin( ∅ ) = 1 / csc ( -∅ )

8 0

3 years ago

4(x+3)-4=8(1/2x+1) i need to find the solution

oee [108]

You can solve this by algebraically as well as graphically. When I tried both ways I got:
solution is x= -2<span />

5 0

4 years ago

Find the length of the curve y = 3/5x^5/3 - 3/4x^1/3 + 6 for 1 < = x < = 8. The length of the curve is . (Type an exact an

Mashutka [201]

Answer:

$\sqrt\frac{387}{20}$

Step-by-step explanation:

$Arc Length =\int\limits^a_b {\sqrt{1+(\frac{dy}{dx})^2 } } \, dx$

$y=\dfrac{3}{5}x^{\frac{5}{3}}- \dfrac{3}{4}x^{\frac{1}{3}}+6$

$\frac{dy}{dx} =x^{\frac{2}{3}}-\dfrac{1}{4}x^{-\frac{2}{3}}$

$1+(\frac{dy}{dx})^2 }=1+(x^{\frac{2}{3}}-\dfrac{1}{4}x^{-\frac{2}{3}})^2\\=1+(x^{\frac{4}{3}}-\dfrac{1}{2}+ \dfrac{1}{16}x^{-\frac{4}{3}})$

$=\dfrac{1}{2}+x^{\frac{4}{3}}+ \dfrac{1}{16}x^{-\frac{4}{3}}$

For the Interval $1\leq x\leq 8$

Length of the Curve $=\int\limits^8_1 {\sqrt{\dfrac{1}{2}+x^{\frac{4}{3}}+ \dfrac{1}{16}x^{-\frac{4}{3}} } } \, dx\\$

Using T1-Calculator

$=\sqrt\frac{387}{20}$

3 0

4 years ago

PLEASE HELP!!!!!!!!!!!!

gulaghasi [49]

Answer:

I didnt get what the photo shows....

Step-by-step explanation:

7 0

3 years ago