Please solve kx-2=7 for x

kolezko [41]

Answer:

10^-5

Step-by-step explanation

Move the decimal to the right 5 places. Moving to the right makes the power a negative, moving to the left would make it a positive.

6 0

3 years ago

Drake rolls two fair number cubes. 1 2 3 4 5 6 1 1 2 3 4 5 6 2 2 4 6 8 10 12 3 3 6 9 12 15 18 4 4 8 12 16 20 24 5 5 10 15 20 25

e-lub [12.9K]

Wouldn’t it be 2/15 chance because there is only two fifteens

7 0

3 years ago

Read 2 more answers

Dos triángulos son semejantes, si sus ángulos son iguales y sus lados proporcionales. Verdadero o falso?

iren2701 [21]

Answer: verdadero.

Step-by-step explanation:

En geometría se dice que dos figuras son semejantes si tienen la misma forma pero no necesariamente el mismo tamaño.

Ahora, lo que define la forma de un triángulo son sus ángulos, entonces si dos triángulos tienen los mismos ángulos, estos triángulos van a tener la misma forma.

Y los lados siendo proporcionales entre ellos (recordar que una relación proporcional es y = k*x) habla de la relación entre los tamaños de los dos triángulos.

Entonces si, "dos triángulos son semejantes, si sus ángulos son iguales y sus lados proporcionales" es verdadero.

5 0

3 years ago

David earned a gross pay of $160 for one week. He worked 20 hours. What is his hourly wage?

NikAS [45]

Answer:

8

Step-by-step explanation:

160 divided by 20 hours = 8.

David has a 8 hourly wage.

5 0

3 years ago

Read 2 more answers

Find the (a) mean, (b) median, (c) mode, and (d) midrange for the data and then (e) answer the given question. Listed below

mafiozo [28]

Answer:

a) $\bar X = 369.62$

b) $Median=175$

c) $Mode =450$

With a frequency of 4

d) $MidR= \frac{Max +Min}{2}= \frac{49+3000}{2}= 1524.5$

<u>e)</u> $s = 621.76$

And we can find the limits without any outliers using two deviations from the mean and we got:

$\bar X+2\sigma = 369.62 +2*621.76 = 1361$

And for this case we have two values above the upper limit so then we can conclude that 1500 and 3000 are potential outliers for this case

Step-by-step explanation:

We have the following data set given:

49 70 70 70 75 75 85 95 100 125 150 150 175 184 225 225 275 350 400 450 450 450 450 1500 3000

Part a

The mean can be calculated with this formula:

$\bar X = \frac{\sum_{i=1}^n X_i}{n}$

Replacing we got:

$\bar X = 369.62$

Part b

Since the sample size is n =25 we can calculate the median from the dataset ordered on increasing way. And for this case the median would be the value in the 13th position and we got:

$Median=175$

Part c

The mode is the most repeated value in the sample and for this case is:

$Mode =450$

With a frequency of 4

Part d

The midrange for this case is defined as:

$MidR= \frac{Max +Min}{2}= \frac{49+3000}{2}= 1524.5$

Part e

For this case we can calculate the deviation given by:

$s =\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}$

And replacing we got:

$s = 621.76$

And we can find the limits without any outliers using two deviations from the mean and we got:

$\bar X+2\sigma = 369.62 +2*621.76 = 1361$

And for this case we have two values above the upper limit so then we can conclude that 1500 and 3000 are potential outliers for this case

5 0

3 years ago