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Dafna11 [192]
3 years ago
12

Please help with these 5 questions, we don't have school cause she got 4 inches of snow and it icy so i don't have any help and

my parents don't know- brainilest when assignment is graded if correct

Mathematics
2 answers:
Cloud [144]3 years ago
7 0

Answer:

For the first question there are 60 pengins

For the 2nd one its 90

Step-by-step explanation:

For 1 its 60 because there are 6 penguins in each colum and 10 rows so then you would do 6 x 10 which is 60.

And for the other one you do 6 x 15 which is 90.

Thats my thinking

denpristay [2]3 years ago
3 0

Answer: Your so lucky I still have school and I'm sick and tired...

Step-by-step explanation:

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Use Lagrange multipliers to find the maximum and minimum values of
marusya05 [52]

The Lagrangian is

L(x,y,\lambda)=x+8y+\lambda(x^2+y^2-4)

It has critical points where the first order derivatives vanish:

L_x=1+2\lambda x=0\implies\lambda=-\dfrac1{2x}

L_y=8+2\lambda y=0\implies\lambda=-\dfrac4y

L_\lambda=x^2+y^2-4=0

From the first two equations we get

-\dfrac1{2x}=-\dfrac4y\implies y=8x

Then

x^2+y^2=65x^2=4\implies x=\pm\dfrac2{\sqrt{65}}\implies y=\pm\dfrac{16}{\sqrt{65}}

At these critical points, we have

f\left(\dfrac2{\sqrt{65}},\dfrac{16}{\sqrt{65}}\right)=2\sqrt{65}\approx16.125 (maximum)

f\left(-\dfrac2{\sqrt{65}},-\dfrac{16}{\sqrt{65}}\right)=-2\sqrt{65}\approx-16.125 (minimum)

5 0
4 years ago
Find the possible values for s in the inequality 12s – 20 ≤ 50 – 3s – 25.        A. s ≤ 9   B. s ≤ 3   C. s ≤ 1/3   D. s ≤ 5/9  
Kitty [74]
The answer wil be B.
7 0
3 years ago
Based on the graph below, which point is a solution?
Butoxors [25]

Answer:

A.(5,1) to

Step-by-step explanation:

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4 0
3 years ago
A distribution in which the frequency is either constantly increasing or constantly decreasing is called a(n):________
BlackZzzverrR [31]

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J Shaped

Step-by-step explanation:

5 0
3 years ago
How do I fill this out? Im not sure how to?
prohojiy [21]

Answer:

z=-21

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We move all terms to the left:

(9-3)/2-((6+z)/5)=0

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We add all the numbers together, and all the variables

-((z+6)/5)+3=0

We multiply all the terms by the denominator

-((z+6)+3*5)=0

We calculate terms in parentheses: -((z+6)+3*5), so:

(z+6)+3*5

We add all the numbers together, and all the variables

(z+6)+15

We get rid of parentheses

z+6+15

We add all the numbers together, and all the variables

z+21

Back to the equation:

-(z+21)

We get rid of parentheses

-z-21=0

We add all the numbers together, and all the variables

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We move all terms containing z to the left, all other terms to the right

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5 0
3 years ago
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