Which estimate is closest to the actual value of (2.99548) ⋅ (1.8342)? CHOOSE ALL THAT APPLY!

Lisa [10]

Answer:

The answer is y=-x+9.

The first thing to do is find where the line intercepts the y-axis, which is at positive 9 so you'll add a +9 to the end of your equation. Next you find the slope and since it's going down left to right, you know it is a negative. Now slope is found by change in y divided by change in x. And since both change and y and change in x are both 1, 1/1 is 1. And since you know it's negative that means the slope is -x. Altogether you get y= -x+9

8 0

2 years ago

Anthony's weight is nine pounds more than twice his brothers weight. Anthony's weighs 59 pounds. how much does his brother weigh

ahrayia [7]

A = Anthony's weight
B = Anthony's brother's weight

A = 2B + 9 Plug in Anthony's weight
59 = 2B + 9 Subtract 9 from both sides
50 = 2B DIvide both sides by B
25 = B Switch the sides to make it easier to read
B = 25

Anthony's brother weighs 25 pounds.

8 0

3 years ago

Read 2 more answers

f(x) = 3 cos(x) 0 ≤ x ≤ 3π/4 evaluate the Riemann sum with n = 6, taking the sample points to be left endpoints. (Round your ans

Kruka [31]

Answer:

$\int_{0}^{\frac{3 \pi}{4}}3 \cos{\left(x \right)}\ dx\approx 3.099558$

Step-by-step explanation:

We want to find the Riemann sum for $\int_{0}^{\frac{3 \pi}{4}}3 \cos{\left(x \right)}\ dx$ with n = 6, using left endpoints.

The Left Riemann Sum uses the left endpoints of a sub-interval:

$\int_{a}^{b}f(x)dx\approx\Delta{x}\left(f(x_0)+f(x_1)+2f(x_2)+...+f(x_{n-2})+f(x_{n-1})\right)$

where $\Delta{x}=\frac{b-a}{n}$ .

Step 1: Find $\Delta{x}$

We have that $a=0, b=\frac{3\pi }{4}, n=6$

Therefore, $\Delta{x}=\frac{\frac{3 \pi}{4}-0}{6}=\frac{\pi}{8}$

Step 2: Divide the interval $\left[0,\frac{3 \pi}{4}\right]$ into n = 6 sub-intervals of length $\Delta{x}=\frac{\pi}{8}$

$a=\left[0, \frac{\pi}{8}\right], \left[\frac{\pi}{8}, \frac{\pi}{4}\right], \left[\frac{\pi}{4}, \frac{3 \pi}{8}\right], \left[\frac{3 \pi}{8}, \frac{\pi}{2}\right], \left[\frac{\pi}{2}, \frac{5 \pi}{8}\right], \left[\frac{5 \pi}{8}, \frac{3 \pi}{4}\right]=b$