The condition for an expression to be an <u>identity </u>is that both sides of equality must give the same value.
In this case, the equation that fulfills that condition is the first equation (1).
<u>Let’s prove it:</u>
1)
Applying distributive property:
Joining together similar terms on both sides of the equality:
<h2>
>>>>>>>This is true and fulfills the condition of identity</h2>
The other equations do not fulfill the condition:
2)
>>>>>>>This is not logic
3)
>>>>>>>This is not logic
4)
>>>>>>>This is not logic
Answer:
p+37 = 2p-50
87
m<I=124
Step-by-step explanation:
Hello :
f(x) = (2x-5)/3
<span>f−1(x) = (3x+5)/2
because : f(x) 0 </span>f−1(x) = x and f−1(x) 0 f(x) = x
f(x) 0 f−1(x) = f( f−1(x) ) = f ((3x+5)/2) = (2(3x+5)/2 - 5))/3 = 3x /3 =x
same cacul for : f−1(x) 0 f(x) = x
-30x - 20: We can see that both numbers have a factor of -10, because 30 and 20 are multiples of 10 and -30x and -20 are both negative. So the factored form is -10(3x + 2).
12x - 28: The greatest common divisor of the two numbers is 4, so the factored form is 4(3x - 7).
-10x - 5: Like the first problem, the biggest factor is -5, so the factored form is -5(2x + 1).