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Step2247 [10]
3 years ago
13

Solve y = 4x – 17 3x + y = 4 with the substitution method PLEASE HELP

Mathematics
2 answers:
expeople1 [14]3 years ago
7 0

Answer:

Step-by-step explanation:

y = 4x – 17..........(1)

3x + y = 4............(2)

Substituting y = 4x - 17 in (2)

3x + 4x - 17 = 4

7x = 4 + 17

7x = 21

x = 21/7

x = 3

Putting x = 3 in equation (1)

y = 4x - 17

y = 4(1) - 17

y = 4 - 17

y = -13

Firdavs [7]3 years ago
3 0

Hey! :)

First, let us learn about substitution.

Let's say we have an equation 3x + 1y = 1 and 1x + 2y = 6

You need to pick one equation to solve for x.

Let's say we picked 1x + 2y = 6 for x to solve for y.

Then you'd solve.

Now onto the equation.

- Substitute 4x−17 for y in 3x+y=4:

3x+y=4

3x+4x−17=4

7x−17=4 - Simplify both sides.

7x−17+17=4+17 Let's add 17 to both sides.

7x=21

Divide both sides by 7.

7x/7 = 21/7

x = 3

Hope you had a great experience on Brainly!

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As part of the underwriting process for insurance, each prospective policyholder is tested for high blood pressure. Let X repres
xxTIMURxx [149]

Answer:

0.053

Step-by-step explanation:

This is a geometric distribution problem.

I'm geometric distribution problem,

E(X) = 1/p

Where;

E(X) is expected value and p is probability of success

Thus;

1/p = 12.5

p = 1/12.5

p = 0.08

Now, to find the probability that the sixth person tested is the first one with high blood pressure, we will use the probability formula in geometric distribution which is;

P(X = k) = qⁿ•p

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Thus;probability that the sixth person tested is the first one with high blood pressure will be expressed as;

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3 0
3 years ago
What inequality sign do you use if c is at most 3
lesya692 [45]
It would be c≤3 as in c is less than or equal to three
5 0
3 years ago
Find a function where f(0)=2 and f(1)=2
xenn [34]

Answer:

Do you want to be extremely boring?

Since the value is 2 at both 0 and 1, why not make it so the value is 2 everywhere else?

f(x) = 2 is a valid solution.

Want something more fun? Why not a parabola? f(x)= ax^2+bx+c.

At this point you have three parameters to play with, and from the fact that f(0)=2 we can already fix one of them, in particular c=2. At this point I would recommend picking an easy value for one of the two, let's say a= 1 (or even a=-1, it will just flip everything upside down) and find out b accordingly:f(1)=2 \rightarrow 1^2+b+2=2 \rightarrow b=-1

Our function becomes

f(x) = x^2-x+2

Notice that it works even by switching sign in the first two terms: f(x) = -x^2+x+2

Want something even more creative? Try playing with a cosine tweaking it's amplitude and frequency so that it's period goes to 1 and it's amplitude gets to 2: f(x) = A cos (kx)

Since cosine is bound between -1 and 1, in order to reach the maximum at 2 we need A= 2, and at that point the first condition is guaranteed; using the second to find k we get 2= 2 cos (k1) = cos k = 1 \rightarrow k = 2\pi

f(x) = 2cos(2\pi x)

Or how about a sine wave that oscillates around 2? with a similar reasoning you get

f(x)= 2+sin(2\pi x)

Sky is the limit.

8 0
2 years ago
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