Answer:
d=4
Step-by-step explanation:
Agency 1:
Total cost of renting a car=24.50d + 15.99
Agency 2:
Total cost of renting a car=27.50d + 3.99
Where, d=No. of days of renting the car
Which equation could be used to find the number of days, d, at which the rental fee is the same for both agencies?
The equation is by equating agency 1 and agency 2 equation
24.50d + 15.99 = 27.50d + 3.99
Collect like terms
24.50d - 27.50d = 3.99 - 15.99
-3d = -12
Divide both sides by -3
d= -12 / -3
=4
d=4
Check
Agency 1:
24.50d + 15.99
= 24.50(4) + 15.99
= 98 + 15.99
= 113.99
Agency 2:
27.50d + 3.99
= 27.50(4) + 3.99
= 110 + 3.99
= 133.99
Answer:
(5 x 15) + (3 x 15) = 120
Step-by-step explanation:
5 x 15 = 75
3 x 15 = 45
75 + 45 = 120
Hope this helps :)
That would be
![x = + \frac{ \sqrt[]{3} }{ \sqrt[]{2} }](https://tex.z-dn.net/?f=x%20%3D%20%20%2B%20%5Cfrac%7B%20%5Csqrt%5B%5D%7B3%7D%20%7D%7B%20%5Csqrt%5B%5D%7B2%7D%20%7D%20)
BTW the plus sign is supposed to have this sign underneath it _
Good luck.
Answer:
5 and 1/2
Step-by-step explanation: 2 goes into 11 5 times without passing it. That one that is left over would be the numerator and 2 as the demonator.
A + c = 824 represents number of tickets to sell
20a + 12c = 13,344 represents cost of each type of ticket
multiply equation 1 by -12 to cancel the variable 'c' and solve for 'a'
-12(a + c = 824)
-12a - 12c = - 9888
20a + 12c = 13,344 add equations together
-----------------------------
8a = 3456 divide both sides by 8
a = 432
To find children's tickets substitute adult numbers back into equation 1.
a + c = 824
432 + c = 824
subtract 432 from both sides
c = 392
adult 432, children 392
