2x+2x+3x+3+3x+3=146
10x+6=146
10x=140
x=14
45 units is the longest side
Hope this helped!!!!!
Answer:
-16
Step-by-step explanation:
1-8-9=-16
I'll be honest, this is a pretty interesting question. I've never seen anything like it before!
We can start off by making equations with the given. If there are 100 heads, that means that the total number of chickens and pigs combined is 100. Thus, we can form our first equation:
p + c = 100
('p' represents number of pigs, and 'c' represents number of chickens)
We also know that there are 270 legs total. Since chickens have 2 and pigs have 4, we can make the following equation:
2c + 4p = 270
I suppose the quickest way to solve for this equation is to use the subtraction method. Put the equations on top of each other:
2c + 4p = 270
c + p = 100
___________
Multiply the bottom equation by -2;
2c + 4p = 270
-2c -2p = 100
____________
"Add" these two equations together:
2c + 4p = 270
-2c -2p = -200
___________
2p = 70
Divide both sides by 2:
p = 35
Ah, finally. Now that we know that there are 35 pigs, input this variable into the first equation to find the number of chickens:
c + 35 = 100
Subtract:
c = 65
There are 35 pigs and 65 chickens
-T.B.
We can find the number of extra clubs in the deck from the given probability, since the probability of drawing a diamond and a club is
but this would imply that
, which suggests we're taking 4 clubs out of the original deck and contradicts the problem statement that there are "too many clubs".
Perhaps the question is providing the probability of drawing a diamond, THEN a club, or vice versa. In that case, we have
and solving gives
, which makes more sense. Then the number of extra spades in the deck must be 2.
Answer: 2x-5y
Step-by-step explanation:
The common term in this expression (GCF) is 5. When you take out the 5, you get 2x-5y. This is the answer.
:)
