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2 years ago

How long does it take for a cyclist to travel 600 meters at a speed of 10 m/s

Mathematics

1 answer:

Wewaii [24]2 years ago

3 0

Time = distance / speed

Time = 600m / 10m/s

Time = 60 seconds (1 minute)

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Luis starts to do a division problem and notices that there is a pattern in the digits to the right of the decimal point.This nu

Assoli18 [71]

Answer: Rational

Step-by-step explanation:

5 0

3 years ago

Brian is riding his bike. He biked a distance of 14 miles at a rate of 14 miles per hour. Rearrange the distance formula, d = rt

xeze [42]

Answer:

60 minutes

Step-by-step explanation -

14=14t

14*1=14

6 0

3 years ago

How do you write 70% as a fraction in simplest form ?

alexdok [17]

70% equals to 70/100 in fraction form.
But, you need to write it in simplest form. so, divide both of them from 10 'cause they both can divide completely by it.
70/100 = 7/10
so, your answer is 7/10

3 0

3 years ago

Evaluate Dx / ^ 9-8x - x2^

Solnce55 [7]

It depends on what you mean by the delimiting carats "^"...

Since you use parentheses appropriately in the answer choices, I'm going to go out on a limb here and assume something like "^x^" stands for $\sqrt x$ .

In that case, you want to find the antiderivative,

$\displaystyle\int\frac{\mathrm dx}{\sqrt{9-8x-x^2}}$

Complete the square in the denominator:

$9-8x-x^2=25-(16+8x+x^2)=5^2-(x+4)^2$

Now substitute $x+4=5\sin y$ , so that $\mathrm dx=5\cos y\,\mathrm dy$ . Then

$\displaystyle\int\frac{\mathrm dx}{\sqrt{9-8x-x^2}}=\int\frac{5\cos y}{\sqrt{5^2-(5\sin y)^2}}\,\mathrm dy$

which simplifies to

$\displaystyle\int\frac{5\cos 
y}{5\sqrt{1-\sin^2y}}\,\mathrm dy=\int\frac{\cos y}{\sqrt{\cos^2y}}\,\mathrm dy$

Now, recall that $\sqrt{x^2}=|x|$ . But we want the substitution we made to be reversible, so that

$x+4=5\sin y\iff y=\sin^{-1}\left(\dfrac{x+4}5\right)$

which implies that $-\dfrac\pi2\le y\le\dfrac\pi2$ . (This is the range of the inverse sine function.)

Under these conditions, we have $\cos y\ge0$ , which lets us reduce $\sqrt{\cos^2y}=|\cos y|=\cos y$ . Finally,

$\displaystyle\int\frac{\cos y}{\cos y}\,\mathrm dy=\int\mathrm dy=y+C$

and back-substituting to get this in terms of $x$ yields

$\displaystyle\int\frac{\mathrm dx}{\sqrt{9-8x-x^2}}=\sin^{-1}\left(\frac{x+4}5\right)+C$

4 0

3 years ago

I am having a conflict with my family what is 7-1×0+3÷3 = ?

ryzh [129]

Follow PEMDAS.

Parenthesis
Exponents
Multiplication & Division
Addition & Subtraction

Alright, do multiplication first, then division. Then, do subtraction then addition.

$7-1*0+3/3= \\ 7-0+3/3= \\ 7 - 0 + 1= \\ 7 + 1 = 8 \\ 7-1*0+3/3 =8$

Hope this helped!

6 0

3 years ago