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scZoUnD [109]
3 years ago
9

Will give brainliest

Mathematics
1 answer:
mariarad [96]3 years ago
6 0

Answer:

8/27

Step-by-step explanation:

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PLS SOLVE THIS ASAP!!!<br> NEED IT NOW
FromTheMoon [43]
The answer would be 36.4
3 0
3 years ago
A single die is rolled twice. Find the probability of rolling an oddnumber the first time and a number greater than 2 the second
harkovskaia [24]

Answer:

1/3.

Step-by-step explanation:

The 2 events are independent so we multiply the 2 probabilities.

Prob(rolling an odd number) = 3/6 = 1/2.

Prob(rolling a number greater than 2) = 4/6 = 2/3.

The required probability = 1/2 * 2/3

= 2/6

= 1/3.

5 0
3 years ago
Which of the following equations have exactly one solution?
Sonja [21]

Answer:

B.

Step-by-step explanation:

Because if you subtract 19x and 18 from each side it wont be 0=0, in other equatins there is infinity solutions

7 0
3 years ago
Quadrilateral STWR is inscribed inside a circle as shown below. Write a proof showing that angles T and R are supplementary.
AlladinOne [14]

Observe the given figure.

Here, angle T and R are the inscribed angles.

And sum of inscribed angles is half of measure of intercepted arcs.

Since, the measure of intercepted arcs is 360 degrees.

Therefore, \angle T + \angle R = \frac{1}{2} \times 360 ^{\circ}

\angle T + \angle R = 180 ^{\circ}

Hence, the sum of the two angles is 180 degrees.

Therefore, these are the supplementary angles.

Therefore, angle T and angle R are supplementary angles.

Hence, proved.

8 0
3 years ago
What are the approximate values of the minimum and maximum points of f(x) = x5 − 10x3 + 9x on [-3,3]?
nika2105 [10]

Answer:

Minimum : -37 at x=2.4 and

Maximum = 37 at x=-2.4.

Step-by-step explanation:

Given:

f(x)=x^5-10x^3+9x; [-3,3]

Explanation:

In order to find minimum/maximum of a function, we need to find the first derivative of the function and then set it equal to 0 to get critical points.

Therefore,

f'(x)=5x^4-30x^2+9

Setting derivative equal to 0, we get

5x^4-30x^2+9=0

On applying quadratic formula, we get

x=2.4, -2.4, -0.7, 0.7.

So, those are critical points of the given function.

Plugging the values x=2.4, -2.4, -0.7, 0.7, -3 and 3 in above function, we get

f(2.4)=(2.4)^5-10(2.4)^3+9(2.4)= -37.01376   : Minimum.

f(-2.4)=(-2.4)^5-10(-2.4)^3+9(-2.4)= 37.01376 : Maximum.

f(0.7)=(0.7)^5-10(0.7)^3+9(0.7) = 3.03807

f(-0.7)=(-0.7)^5-10(-0.7)^3+9(-0.7) = -3.03807

f(-3)=(-3)^5-10(-3)^3+9(-3) =0

f(3)=(3)^5-10(3)^3+9(3) =0

Therefore the approximate values of the minimum and maximum points of f(x) = x^5- 10x^3+ 9x on [-3,3] are:

Minimum : -37 at x=2.4 and

Maximum = 37 at x=-2.4.


7 0
3 years ago
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