Let's begin noting that a triangle is isosceles if and only if two of its angles are congruent. We can thus find the angle <ABP, recalling that the sum of the interior angles of a triangle is equal to 180°. 

Finally, let point K be the intersection between segments BC and PQ, and let's note that the triangle PQB is a right isosceles triangle, since all the angles in a square are equal to 90°, and the two triangles APB and BQC are congruent. 
Therefore, the angle BKQ is equal to 180-50-45=85°. 
Of course angle BKP=180-85=95°.
Hope this helps :) 
 
        
             
        
        
        
Answer:
which grade u r in I'm in 10th grade and Indian 
 
        
                    
             
        
        
        
Answer:
Step-by-step explanation:
the square root of 12 is 3.4 so the answer is 3.4
 
        
             
        
        
        
Answer:
x = 13, y = 7
Step-by-step explanation:
The diagonals of a parallelogram bisect each other, thus
x - 7 = 6 ( add 7 to both sides )
x = 13
and
2y - 6 = 8 ( add 6 to both sides )
2y = 14 ( divide both sides by 2 )
y = 7
 
        
             
        
        
        
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