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Ksju [112]
4 years ago
7

What is the measurement of angle POR

Mathematics
1 answer:
IgorLugansk [536]4 years ago
8 0

Let us observe the given figure,

When two lines intersect each other, the angles opposite to each other are Vertically Opposite Angles. Vertically opposite angles are always equal in measure.

As, we can observe that the given lines intersect each other, and they form vertically opposite angles as \angle POR , \angle SOQ and  \angle POS , \angle ROQ

Therefore, \angle POR = \angle SOQ

Substituting the given measures of the angles, we get

91-x^\circ = x+ 7^\circ

91-7 = x + x

84 = 2x

x = \frac{84}{2}

So, x = 42^\circ

Since, the measure of angle POR = (91-x)^\circ

= (91-42)^\circ

= 49^\circ

Therefore, the measure of angle POR is 49 degrees.

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Which is the constant of proportionality for the relationship shown in the graph?
vladimir2022 [97]

Answer:

COP: 2X

Step-by-step explanation:

K= Y/X

K= 4/2

K= 8/4

K= 12/6

K=16/8

8 0
3 years ago
Jan uses 22.5 gallons of water in the shower. This amount is 7.5 gallons less than what she uses when washing her clothes. Write
arsen [322]

22.5 (shower) = X (variable used in place of the amount of water she uses to wash clothes) - 7.5 (the amount she used in the shower is 7.5 gallons less than she uses for washing clothes)

22.5 = X - 7.5 《 This is the equation.

Solve is by adding 7.5 to both sides to cancel out the negative 7.5 and you get (X = 30).

3 0
3 years ago
A group of retired admirals, generals, and other senior military leaders, recently published a report, "Too Fat to Fight". The r
weqwewe [10]

Answer:

z=\frac{0.694 -0.75}{\sqrt{\frac{0.75(1-0.75)}{180}}}=-1.735  

p_v =P(z  

If we compare the p value obtained and the significance level given \alpha=0.05 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of americans between 17 to 24 that not qualify for the military is significantly less than 0.75 or 75% .  

Step-by-step explanation:

1) Data given and notation  

n=180 represent the random sample taken  

X=125 represent the number of americans between 17 to 24 that not qualify for the military

\hat p=\frac{125}{180}=0.694 estimated proportion of americans between 17 to 24 that not qualify for the military

p_o=0.75 is the value that we want to test  

\alpha=0.05 represent the significance level  

Confidence=95% or 0.95  

z would represent the statistic (variable of interest)  

p_v represent the p value (variable of interest)  

2) Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that less than 75% of Americans between the ages of 17 to 24 do not qualify for the military :  

Null hypothesis: p\geq 0.75  

Alternative hypothesis:p < 0.75  

When we conduct a proportion test we need to use the z statistic, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.  

3) Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.694 -0.75}{\sqrt{\frac{0.75(1-0.75)}{180}}}=-1.735  

4) Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The significance level provided \alpha=0.05. The next step would be calculate the p value for this test.  

Since is a left tailed test the p value would be:  

p_v =P(z  

If we compare the p value obtained and the significance level given \alpha=0.05 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of americans between 17 to 24 that not qualify for the military is significantly less than 0.75 or 75% .  

6 0
3 years ago
Use the digits 2, 3, and 5 to create a fraction and a whole number with a product greater than 2
kupik [55]
The fractions which cannbe formed are: 2/3, 3/2, 2/5, 5/2, 3/5 and 5/3.
Now, we find the products with the third number:
2/3*5= 10/3 = 3.33 > 2
3/2*5 = 15 >2= 7.5 > 2
2/5*3= 6/5 (rejected)
5/2*3 = 15/2 > 2
3/5*2= 6/5 (rejected)
5/3*2 = 15/2 = 7.5> 2
5 0
3 years ago
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i answered the same question on anoter website!!!
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