This is a sum and difference problem, with the equations
R-N=35
R+N=635
The solution of which is
R=(635+35)/2=335
N=(635-35)/2=300
In general, the sum and difference problem can be solved (most of the time mentally) using
Larger number = (sum + difference)/2
Smaller number = (sum - difference)/2
Given:
The discount is 25%.
The selling price of the shirt after the sale is $20.99.
To find:
The selling price of the shirt before the sl;e
Explanation:
Let the old price be x.
The equation can be framed as follows,
Final answer:
The selling price of the shirt before the sale is $27.99.
Answer:
Step-by-step explanation:
hello :
f(x) = (x+3)(x+6)(x+8)
1. 10 boxes
2. about 20
3. 6x100 + (6x9)x10 + 6x8
Answer:
C. 8 ft.
Step-by-step explanation:
start by identifying your a (1), b (6), and c(-112). you plug them into the quadratic formula or by using this calculator https://www.calculatorsoup.com/calculators/algebra/quadratic-formula-calculator.php. the two solutions will be x = 8 and x = -14, but of course the reasonable answer is 8 and none of the choices are -14.
