Answer:
Option A is correct.
Step-by-step explanation:
As we see the graph, we can say that the correct statement is :
A.)All repairs requiring 1 hour or less have the same labor cost. We can see that the coat from 0 hours to 1 hour is $50. So, the number of hours falling in this range has the same repairing cost.
B.) Labor costs the same no matter how many hours are used for a repair. This is wrong as the graph is increasing after 1 hour.
C.) Labor costs for a repair are more expensive as the number of hours increases. This is wrong as the hours are increasing from 0.25 to 0.5 then to 0.75 but they all have the same cost.
D.)There is no cost of labor for a repair requiring less than 1 hour. This is also wrong. The cost is $50.
2a.) 8.8 x 4 = 35.2g
2b.) 35.2 x 30 = 1056g or 1.056kg
Answer:
0.684
Step-by-step explanation:
According to the scenario, computation of the given data are as follows
Seasonal index = Average value for July ÷ Average over all months
Where, Average value for July = ( 110 + 150 + 130 ) ÷ 3
= 390 ÷ 3 = 130
And, average over all months = 190
So by putting the value in the formula, we get
Seasonal index = 130 ÷ 190
= 0.684211 or 0.684
Hence, approximate seasonal index for July is 0.684.
Answer:
Vota Trump
Step-by-step explanation:
Answer:
First option: cos(θ + φ) = -117/125
Step-by-step explanation:
Recall that cos(θ + φ) = cos(θ)cos(φ) - sin(θ)sin(φ)
If sin(θ) = -3/5 in Quadrant III, then cos(θ) = -4/5.
Since tan(φ) = sin(φ)/cos(φ), then sin(φ) = -7/25 and cos(φ) = 24/25 in Quadrant II.
Therefore:
cos(θ + φ) = cos(θ)cos(φ) - sin(θ)sin(φ)
cos(θ + φ) = (-4/5)(24/25) - (-3/5)(-7/25)
cos(θ + φ) = (-96/125) - (21/125)
cos(θ + φ) = -96/125 - 21/125
cos(θ + φ) = -117/125
