so 16 pizzas are pepperoni
19 pizzas are cheese
And the rest is Veggie
So now add 16 and 19 which is 35
Now subtract that from 50 which is 15
So 15 pizzas were Veggie pizzas
Do you solve for area
2 answers:
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so 16 pizzas are pepperoni
19 pizzas are cheese
And the rest is Veggie
So now add 16 and 19 which is 35
Now subtract that from 50 which is 15
So 15 pizzas were Veggie pizzas
Answer:
by using Pythagoras theorm
Step-by-step explanation:
<h2>HOPE IT WILL HELP YOU✌✌✌✌✌</h2>Answer:
Anything in the form x = pi+k*pi, for any integer k
These are not removable discontinuities.
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Explanation:
Recall that tan(x) = sin(x)/cos(x).
The discontinuities occur whenever cos(x) is equal to zero.
Solving cos(x) = 0 will yield the locations when we have discontinuities.
This all applies to tan(x), but we want to work with tan(x/2) instead.
Simply replace x with x/2 and solve for x like so
cos(x/2) = 0
x/2 = arccos(0)
x/2 = (pi/2) + 2pi*k or x/2 = (-pi/2) + 2pi*k
x = pi + 4pi*k or x = -pi + 4pi*k
Where k is any integer.
If we make a table of some example k values, then we'll find that we could get the following outputs:
- x = -3pi
- x = -pi
- x = pi
- x = 3pi
- x = 5pi
and so on. These are the odd multiples of pi.
So we can effectively condense those x equations into the single equation x = pi+k*pi
That equation is the same as x = (k+1)pi
The graph is below. It shows we have jump discontinuities. These are <u>not</u> removable discontinuities (since we're not removing a single point).
