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3 years ago

Find the displacement of a particle from t = 0 to t - 5, given v(t) = e^2sint - 1

Mathematics

1 answer:

andre [41]3 years ago

4 0

Answer:

I found it on quizlet and it help me a lot :)

Step-by-step explanation:

just look up your question on quizlet then tap on a quiz then tap on view flashcards and once you see your question stop and tap the flashcard then the flashcard will flip and your answer will be on the back of it

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For the following system, use the second equation to make a substation for y in the first equation. 2x+y=6 y=3x+4. What is the r

Vera_Pavlovna [14]

2x+y=6
y=3x+4

The resulting equation is
5x=2
where
x=2/5

3 0

3 years ago

Find all values of $x$ such that $\dfrac{x}{x+4} = -\dfrac{9}{x+3}$. If you find more than one value, then list your solutions i

mixer [17]

We start with

$\dfrac{x}{x+4} = -\dfrac{9}{x+3}$

Assuming that $x \notin \{-4,\ -3\}$ we can cross multiply the equation:

$x(x+3) = -9(x+4) \iff x^2+3x=-9x-36 \iff x^2+12x+36=0$

You can recognize the perfect square pattern in the quadratic equation:

$x^2+12x+36 = (x)^2 + 2\cdot x \cdot 6 + (6)^2 = (x+6)^2$

So, we have

$x^2+12x+36=0 \iff (x+6)^2 = 0 \iff x+6=0 \iff x=-6$

Which is the only solution, with multiplicity 2.

8 0

4 years ago

Read 2 more answers

Find r and s. PLS HELP AND QUICK!

zavuch27 [327]

Answer:

r=12

S=24

Step-by-step explanation:

$\tan(60) = \frac{12 \sqrt{3} }{r} \\ \sqrt{3} = \frac{12 \sqrt{3} }{r} \\ r = 12 \\ \\ \\ \sin(60) = \frac{12 \sqrt{3} }{s} \\ \frac{ \sqrt{3} }{2} = \frac{12 \sqrt{3} }{s} \\ s = 24$

I hope I helped you^_^

5 0

3 years ago

Select the correct answer

salantis [7]

Answer:

Step-by-step explanation:it is really too risky to use credit card online because for someone who doesnt now if the busines is really considered as a trustful source or just a scam.

3 0

4 years ago

-9+6-(-2)= Evaluate the expression

Sunny_sXe [5.5K]

Answer:

Step-by-step explanation:

do the stuff inside the parentheses

*double negatives become positives*

6*2=12

-9+12

pls mark me brainliest

3 0

4 years ago