All categories

2 years ago

Hellllp meeeee aaaaa

Mathematics

1 answer:

drek231 [11]2 years ago

3 0

Answer:

Step-by-step explanation:

y = (-2/5)x + 1

By inspection of the equation, the slope of the line is -2/5 and the y-intercept is 1.

Therefore, we can immediately discount option B and D, as their y-intercepts are NOT 1.

Find the point where the line crosses the x-axis by setting the equation to 0 and solving for x:

0 = (-2/5)x + 1

⇒ -1 = (-2/5)x

⇒ -5 = -2x

⇒ x = 5/2

Therefore, the line of the function intersects the x-axis at x = 5/2 = 2.5

From inspection of the graphs, the line in option A intersects the x-axis at 2.5. Therefore, this is the correct graph.

You might be interested in

If you plot and connect these points P1(3,2) and P2(6,8) , what figure is Formed? What is the Direction?

Sergio [31]

Answer:

Please check the explanation.

Step-by-step explanation:

Given the points

P1(3, 2)

P2(6, 8)

When we plot P1(3, 2) and P2(6, 8), we determine the line segment P1P2.

The direction of the segment is from P1 to P2.

Determining the length of the segment P1P2.

$\:l=\:\sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}$

$=\sqrt{\left(6-3\right)^2+\left(8-2\right)^2}$

$=\sqrt{3^2+6^2}$

$=\sqrt{45}$

$=\sqrt{5}\sqrt{3^2}$

$=3\sqrt{5}$

Thus, the length of the segment is:

$\:\:\:l=3\sqrt{5}$

Determining the equation of a line containing the segment P1P2

Given the points

P1(3, 2)

P2(6, 8)

Finding the slope between P1(3, 2) and P2(6, 8)

$\mathrm{Slope}=\frac{y_2-y_1}{x_2-x_1}$

$\left(x_1,\:y_1\right)=\left(3,\:2\right),\:\left(x_2,\:y_2\right)=\left(6,\:8\right)$

$m=\frac{8-2}{6-3}$

$m=2$

Using the line point-slope form of the line equation

$y-y_1=m\left(x-x_1\right)$

where m is the slope of the line and (x₁, y₁) is the point

substituting the values m = 2 and the point (3, 2)

$y-2=2\left(x-3\right)$

Add 2 to both sides

$y-2+2=2\left(x-3\right)+2$

$y=2x-4$

Thus, the equation of a line containing the line segment P1P2 is:

$y=2x-4$

8 0

3 years ago

Help pleaseeeeeeeeeeee

Yuliya22 [10]

Answer:

x = 1

GF = 12

GH = 15

FH = 3

Step-by-step explanation:

G___F___H

GH = GF + FH

11x +4 = ( 3x +9) + (5x-2)

11x+4= 8x + 7

11x - 8x = 7-4

3x = 3

x =3/3

x = 1

GF = 3x + 9 = 3(1)+9=3+9=12

GH = 11x +4= 11(1)+4=11+4 = 15

FH = 5x - 2 = 5(1) - 2 = 5 - 2 = 3

I hope I helped you^_^

5 0

3 years ago

Solve the system of equations above using it elimination write your answer in the form (x,y) 8X + Y = -16-3X + Y = -5

wlad13 [49]

Given the system of the equation below;

$\begin{gathered} 8x+y=-16----(1) \\ -3x+y=-5----(2) \end{gathered}$

We can use the elimination method to solve the systems of equations

Step 1: Subtract equation 2 from equation 1 and solve for x

$\begin{gathered} 8x+y-(-3x+y)=-16-(-5) \\ 8x+y+3x-y=-16+5 \\ 11x=-11 \\ \frac{11x}{11}=-\frac{11}{11} \\ x=-1 \end{gathered}$

Step 2: Sustitute x = 1 in equation 1

$\begin{gathered} 8(-1)+y=-16 \\ -8+y=-16 \\ y=-16+8 \\ y=-8 \end{gathered}$

Therefore, the solution to the system of equation is

$(-1,-8)$

4 0

2 years ago

A.75/1 dollars per daythe cost $75 for each day.

Rama09 [41]

Answer:

Step-by-step explanation:

Count by 25. Its a no-brainer honestly.

5 0

3 years ago

Read 2 more answers

To finish a project, you need to paint the lateral surfaces of a cube with side length 2.5 inches. Find the area that you need t

valentina_108 [34]

Answer:

$25 in^2$

Step-by-step explanation:

We want to find the lateral surface area of the cube.

The lateral surface area of a cube is given as:

$A = 4a^2$

where a = length of side of the cube

Therefore, given that the length of the side of the cube is 2.5 inches, the area you need to paint is:

$A = 4 * 2.5^2\\A = 25 in^2$

6 0

3 years ago