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3 years ago

Can y’all help meeeeeeeeeeeeeee

Mathematics

2 answers:

Alekssandra [29.7K]3 years ago

4 0

Answer:B

Step-by-step explanation:

mixas84 [53]3 years ago

4 0

Answer:

B- $x\leq 1$

Step-by-step explanation:

On an inequality graph when the dot is filled in that means it is $\leq$ or $\geq$ .

So, on this graph, the dot is filled in and pointing to the right.

Therefore, x is less than or equal to 1

or, $x\leq 1$

You might be interested in

How to solve the exponent

andrey2020 [161]

Answer:

- 7

Step-by-step explanation:

Step 1:

8 ÷ 2³ - 16 ÷ 2 Equation

Step 2:

8 ÷ 8 - 16 ÷ 2 Exponents

Step 3:

1 - 16 ÷ 2 Divide

Step 4:

1 - 8 Divide

Answer:

- 7

PEMDAS:

P: Parentheses

E: Exponents

M: Multiplication

D: Division

A: Addition

S: Subtraction

Hope This Helps :)

5 0

3 years ago

Read 2 more answers

Simplify the following expression. cot^2x secx-cosx

Solnce55 [7]

ANSWER

$\cos(x) \cot ^{2} (x)$

EXPLANATION

The given expression is;

$\cot^{2} (x) \sec(x) - \cos(x)$

Change everything to

$\sin(x)$

and

$\cos(x)$

This implies that,

$\frac{ \cos^{2} (x) }{ \sin^{2} (x) } \times ( \frac{1}{ \cos(x) } )- \cos(x)$

Cancel the common factors,

$\frac{ \cos(x) }{ \sin^{2} (x) } \times ( \frac{1}{1} )- \cos(x)$

$\frac{ \cos(x) }{ \sin^{2} (x) }- \cos(x)$

$\frac{ \cos(x) - \sin ^{2} (x) \cos(x) }{ \sin^{2} (x) }$

$= \frac{ \cos(x)(1 - \sin ^{2} (x) ) }{ \sin^{2} (x) }$

$= \frac{ \cos(x)(\cos^{2} (x) ) }{ \sin^{2} (x) }$

$= \cos(x) \cot^{2} (x)$

6 0

3 years ago

Volume of 7/2, 7/5, and 5

FinnZ [79.3K]

Answer:

7/2.7/5.5 = 140

297

≅ 0.4713805

Step-by-step explanation:

Divide: 7 / 2.7 = 7

· 10

= 7 · 10

1 · 27

= 70

To divide one fraction by another, invert (turn upside-down) the second fraction, then multiply.

Conversion a decimal number to a fraction: 5.5 = 55

= 11

Divide: 70

: 5.5 = 70

· 2

= 70 · 2

27 · 11

= 140

297

To divide one fraction by another, invert (turn upside-down) the second fraction, then multiply.

8 0

3 years ago

6 = 14 - x One step equations review

Ymorist [56]

Answer:

x = 8

Step-by-step explanation:

6 = 14 - x

chance the equation around so it is solvable

14 - x = 6

14 - 6 = x

now solve

14 - 6 = 8

that means x equals 8 so

6 = 14 - 8

4 0

3 years ago

Read 2 more answers

Solve the linear differential equation 2xy' + y = 2√x

77julia77 [94]

Answer:

Step-by-step explanation:

General form of the linear differential equation can be written as:

$\frac{dy}{dx}+P(x)y=Q(x)$

For this case, we can rewrite the equation as:

$\frac{dy}{dx}+\frac{1}{2x}y=\frac{\sqrt{x}}{x}$

Here $P(x) =\frac{1}{2x}; Q(x)=\frac{\sqrt{x}}{x}$

To find the solution (y(x)), we can use the integration factor method:

$Fy(x)=\int Q(x)Fdx+C \rightarrow F=e^{\int P(x)dx$

Then $F=e^{\int \frac{1}{2x}dx}=e^{\frac{1}{2}\ln|x|\right}=\sqrt{|x|}$

So, we can find:

$y\sqrt{|x|}=\int \frac{\sqrt{x}\sqrt{|x|}}{x}dx+C$

Suppose that $x\in \double R$ , then $\sqrt{|x|}=\sqrt{x}$ , and we find:

$y\sqrt{x}=x+C \rightarrow y(x)=\sqrt{x}+\frac{C\sqrt{x}}{x}$

To check our solution is right or not, put your y(x) back to the ODE:

$y' = \frac{1}{2\sqrt{x}}-\frac{C}{2\sqrt{x^{3}}}$

$2xy'=\frac{x-C}{\sqrt{x}}$

$2xy'+y=\frac{x-C}{\sqrt{x}}+\sqrt{x}+\frac{C\sqrt{x}}{x}=2\sqrt{x}$

(it means your solution is right)

3 0

2 years ago