35 would be the answer. 45+35=80 and 45 is 10 more than 35
Answer:
2 points throw = 37
3 points throw = 11
Step-by-step explanation:
Given that:
Let number of
2 points = x ; 3 points = y
x + y = 48 - - - (1)
2x + 3y = 107 ---(2)
x = 48 - y
Then ;
2(48 - y) + 3y = 107
96 - 2y + 3y = 107
96 + y = 107
y = 107 - 96
y = 11
From (1)
x = 48 - 11
x = 37
2 points throw = 37
3 points throw = 11
If you want to multiply (2*x + 5) and (2*x - 5), you can do this using the following steps:
(2*x + 5) * (2*x - 5) = 4*x^2 - 10*x + 10*x - 25 = 4*x^2 - 25
The correct result is 4*x^2 - 25.
1250x.08= 100+1250= 1350 / 120 is 11.25 so 11 months of paying $120 leaves a $30 12th month payment.
<h2>
Question:</h2>
Find k if (x+1) is a factor of 2x³ + kx² + 1
<h2>
Answer:</h2>
k = 1
<h2>
Step-by-step explanation:</h2>
The factor of a polynomial F(x) is another polynomial that divides evenly into F(x). For example, x + 3 is a factor of the polynomial x² - 9.
<em>This is because;</em>
i. x² - 9 can be written as (x - 3)(x + 3) which shows that both (x - 3) and (x + 3) are factors.
ii. If x = -3 is substituted into the polynomial x² - 9, the result gives zero. i.e
=> (-3)² - 9
=> (9) - 9 = 0
Therefore, if (x + a) is a factor of a polynomial, substituting x = -a into the polynomial should result to zero. This also means that, if x - a is a factor of a polynomial, substituting x = a into the polynomial should give zero.
<em><u>From the question</u></em>
Given polynomial: 2x³ + kx² + 1
Given factor: x + 1.
Since x + 1 is a factor of the polynomial, substituting x = -1 into the polynomial should give zero and from there we can calculate the value of k. i.e
2(-1)³ + k(-1)² + 1 = 0
2(-1) + k(1) + 1 = 0
-2 + k + 1 = 0
k - 1 = 0
k = 1
Therefore the value of k is 1.
