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3 years ago

What is the maximun number of trails Charlie could fit in a single picture?

Mathematics

1 answer:

Strike441 [17]3 years ago

7 0

Well he would only be able to get 3 trails at the max. I tried adding lots od different paths together and they all went over 180 degrees if there was more than 3 some went over when there was less then 3. So at the max he could fit 3 trails.

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Express the confidence interval

marissa [1.9K]

Answer:

$\hat p = \frac{0.244+0.326}{2}=0.285$

$ME = \frac{0.326-0.244}{2}=0.041$

$0.285 \pm 0.041$

Step-by-step explanation:

For this case we have a confidence interval given as a percent:

$24.4\% \leq p \leq 32.6\%$

If we express this in terms of fraction we have this:

$0.244 \leq p \leq 0.326$

We know that the confidence interval for the true proportion is given by:

$\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

And thats equivalent to:

$\hat p \pm ME$

We can estimate the estimated proportion like this:

$\hat p = \frac{0.244+0.326}{2}=0.285$

And the margin of error can be estimaed using the fact that the confidence interval is symmetrical

$ME = \frac{0.326-0.244}{2}=0.041$

And then the confidence interval in the form desired is:

$0.285 \pm 0.041$

7 0

3 years ago

This is a question I am needing help with

Solnce55 [7]

Answer:

Step-by-step explanation:

y intercept is b, so in the equation so far it is

y=mx+(5)

the slope is m, so

y=(-3)x+5

the answer is D.

8 0

3 years ago

PLEASE ANSWER I WILL MARK THE BRAINIEST ANSWER :)<br><br>factorise: X^2 + 10x + 16

Damm [24]

Answer:

(x+2)(x+8)

Step-by-step explanation:

1.)find factors of the third expression(16)that will add up to give the second expression(10)

16=2×8. 10=2+8

2.)substitute those factors inplace of 10

${x}^{2} + 10x + 16$

$x {}^{2} + 2x + 8x + 16$

3.)factorise using grouping method

$( {x}^{2} + 2x) + (8x + 16)$

$x(x + 2) + 8(x + 2)$

$= (x + 2)(x + 8)$

3 0

2 years ago

For an arithmetic sequence, a35=57. If the common difference is 5. Find a1 and the sum of the first 61 terms.

Flauer [41]

$\displaystyle\bf\\a_{35}=57\\r=5\\----\\a_1=?\\S_{61}=?\\----\\Solve:\\1)\\a_1=a_{35}-(35-1)\times r=57-34\times 5=57-170=-113\\\boxed{\bf a_1=-113}\\\\$

$\displaystyle\bf\\2)\\A_{61}=a_1+(61-1)\times r=-113+60\times5=-113+300=187\\\\S_{61}=(-113)+(-108)+(-103)+...+(-8)+(-3)+2+7+12+...+187\\\\S_{61}=SA+SB\\\\SA=(-113)+(-108)+(-103)+...+(-8)+(-3)=-(3+8+103+108+113)\\\\n=\frac{113-8}{5}+1=\frac{105}{5}+1=21+1=22~terms\\SA=-\Big( \frac{n(113+3)}{2} \Big)=-\Big( \frac{22\times116}{2} \Big)=-11\times116 =-1276$

$\displaystyle\bf\\SB=2+7+12+...+187\\\\n=\frac{187-2}{5}+1=\frac{185}{5}+1=37+1=38~terms\\\\SB=\frac{n(187+2)}{2}=\frac{38\times189}{2}=19\times189=3591\\\\S_{61}=SA+SB=-1276+3591=2315\\\\\boxed{\bf S_{61}=2315}$

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3 years ago

PLZ ANSWER CORRECTLY 1 2⁄6 ÷ 4 1⁄3

JulijaS [17]

Answer:

0.30715935334

Step-by-step explanation:

8/6 ÷ 13/3

1.33÷ 4.33

0.30715935334

5 0

3 years ago

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What is the maximun number of trails Charlie could fit in a single picture?​

What is the maximun number of trails Charlie could fit in a single picture?