Answer:
26,880
Step-by-step explanation:
Do 25,600 times .05 to get 1,280, then add 1,280 to get the answer.
I would guess they're referring to some general form first<span>f(x)=alog(x−h)+k</span>Where 'h' represents horizontal shifts, 'k' vertical shifts and 'a' stretches the function. "a" will also reflect the function across the x-axis if the value is negative. But NOT across the y-axis. I hope that's the place they wanted to put the a at least
Answer:
Step-by-step explanation:
The problem states that there are only two types of busses - M104 and M6 with probable occurence of 0.6 and 0.4 respectively.
If the average number of busses arriving per hour is λ, the average number of M6 busses per hour is 0.4λ
Now consider a set of 3 M6 busses as an event. The average number of such events per hour will be
μ = 0.4λ / 3
The expected number of hours for the event "THIRD M6 arrives", let's say X is
E[X] = 1 / μ ( exponential distribution) = 3 / 0.4λ
= 7.5 / λ
The variance of event X is =
![Var[x] = \frac{1}{U^2} = \frac{56.25}{\lambda ^2}](https://tex.z-dn.net/?f=Var%5Bx%5D%20%3D%20%5Cfrac%7B1%7D%7BU%5E2%7D%20%3D%20%5Cfrac%7B56.25%7D%7B%5Clambda%20%5E2%7D)
Here is how you would work it out step by step.
You have to factor the equation you're given. (To check you factorization you can "FOIL" it and make sure it matches the original equation)
Then set the two answers you get from FOILing to zero and you should get your answers.
Standard form means:
Ax+By=C
Where A is the coefficient of x, B is the coefficient of y, and C is the y intercept.
It's true that some of those say the same thing but your answer must be in that form because that is what the question asks. So it should be 2x+y=-1