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3 years ago

Can someone please help me with math.

Mathematics

1 answer:

valentina_108 [34]3 years ago

6 0

The first one is B hope this helps

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Examine the functions below. Which statement is true?

Alenkasestr [34]

Answer:

Equation 2 is non-linear, Equation 1 is linear.

Step-by-step explanation:

A linear equation is an equation with a constant gradient and can be expressed in the form y = mx + c. Hence Equation 1 Satisfies this as it is in that form and has a constant gradient of 4. Equation 2 is not in the form y = mx + c since there is a square and hence its non-linear.

8 0

3 years ago

Plz help ASAP!!!!!!<br> WILL MARK BRAINLIEST !!!!!!!!

34kurt

Answer:

triangle MRP and triangle NPR looks like the right answer.

the selected option should be correct.

6 0

3 years ago

Read 2 more answers

Reparametrize the curve with respect to arc length measured from the point where t = 0 in the direction of increasing t. (Enter

jolli1 [7]

Answer:

the answer is incomplete, below is the complete question

"Reparametrize the curve with respect to arc length measured from the point where t = 0 in the direction of increasing t. (Enter your answer in terms of s.) r(t) = 3ti + (1 - 4t)j + (1 + 2t)k r(t(s)) ="

answer

$r(t(s)) = \frac{3s}{\sqrt{29} } i + (1 -\frac{4s}{\sqrt{29} }t)j + (1 + \frac{2s}{\sqrt{29} })k$

Step-by-step explanation:

The step by step procedure is to first determine the differentiate the given vector function

r(t) = 3ti + (1 - 4t)j + (1 + 2t)k

$\frac{d(r(t) = 3ti + (1 - 4t)j + (1 + 2t)k)}{dt} \\r'(t)=3i-4j+2k\\$

since s(t) is the arc length for r(t), which is define as

$s(t)=\int\limits^t_0 {||r'(t)||} \, dt$

if we substitute the value of r'(t) we arrive at

$s(t)=\int\limits^t_0 {||r'(t)||} \, dt\\s(t)=\int\limits^t_0 {\sqrt{3^{2} +4^{2}+2^{2}} \, dt\\s(t)=\int\limits^t_ 0{\sqrt{29} } \, dx\\$

$s(t)=\int\limits^t_ 0{\sqrt{29} } \, dx\\\\s(t)=\sqrt{29} t\\hence \\t(s)=\frac{s}{\sqrt{29} }$

substituting the value of t in to the given vector equation we have

$r(t(s)) = \frac{3s}{\sqrt{29} } i + (1 -\frac{4s}{\sqrt{29} }t)j + (1 + \frac{2s}{\sqrt{29} })k$

4 0

3 years ago

Solve.

Feliz [49]

The answer is x>-11/24

4 0

4 years ago

Read 2 more answers

Determine whether or not the vector field is conservative. if it is conservative, find a function f such that f = ∇f. (if the ve

sweet [91]

A conservative vector field $\mathbf f$ has curl $\nabla\times\mathbf f=\mathbf0$ . In this case,

$\nabla\times\mathbf f=12xy^2z(1-z)\,\mathbf j+4yz^2(2z-3x)\,\mathbf k\neq\mathbf 0$

so the vector field is not conservative.

3 0

3 years ago