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3 years ago

Is this the right answer

Mathematics

1 answer:

Lelechka [254]3 years ago

3 0

Answer:

ummm im fairly sure, yes

Step-by-step explanation:

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Triangle CDA is the image of triangle ABC after a 180° rotation around the midpoint of segment AC. Triangle ECB is the image of

seropon [69]

Answer:equal and parallel opposite sides

Step-by-step explanation:

equal sides

parallel opposite sides

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4 years ago

Find the area of a circle with a radius of 5 feet. Round your answer to the nearest tenth.

klio [65]

Answer:

78.6

Step-by-step explanation:

Area of circle = Pi*r^2

r=5

for pi use calculator or pi=3.142

area =Pi*r2=(3.142)*5^2=(3.142)*25=78.55 = 78.6 (1 decimal place which is same with tenth)

7 0

3 years ago

Order from least to greatest

ddd [48]

Your answer will be :

the square root of 14, the square root of 54/3, 6.8, the square root of 26/3.

7 0

3 years ago

In a five-card poker hand, what is the probability of being dealt exactly one nine and no picture cards?

earnstyle [38]

Answer:

0.0907

Step-by-step explanation:

There are 12 picture cards

There are 4 9's

There are 52-12-4 = 36 cards that are not 9's and not picture cards

(5*58905)/(52C5)

3 0

3 years ago

A 4-foot tall child walks directly away from a 12-foot tall lamppost at 2 mph. How quickly is the length of her shadow increasin

xz_007 [3.2K]

Answer:

The length of the shadow is increasing with the rate of 1.5 feet per sec

Step-by-step explanation:

Let AB and CD represents the height of the lamppost and child respectively ( shown below )

Also, let E be a point represents the position of child.

In triangles ABE and CDE,

$\angle ABE\cong \angle CDE$ ( right angles )

$\angle AEB\cong \angle CED$ ( common angles )

By AA similarity postulate,

$\triangle ABE\sim \triangle CDE$

∵ Corresponding sides of similar triangles are in same proportion,

$\implies \frac{AB}{CD}=\frac{BE}{DE}$

We have, AB = 12 ft, CD = 4 ft, BE = BD + DE = 6 + DE,

$\implies \frac{12}{4}=\frac{6+DE}{DE}$

$12DE = 24 + 4DE$

$8DE = 24$

$DE=3$

Now, the speed of walking = 2 mph = $\frac{2\times 5280}{3600}\approx 2.933\text{ ft per sec}$

Note: 1 mile = 5280 ft, 1 hour = 3600 sec

Thus, the time taken by child to reach at E

$= \frac{\text{Walked distance}}{\text{Walking speed}}$

$=\frac{6}{2.933}$

= 2.045 hours

Hence, the change rate in the length of shadow

$= \frac{\text{Length of shadow}}{\text{Time taken}}$

$=\frac{3}{2.045}$

= 1.5 ft per sec.

3 0

3 years ago

Is this the right answer​

Is this the right answer