Answer:
I blieve that X would be 9 , good luck ^^
The interquartile range (IQR) is 20
You find this by subtracting the values of Q3 and Q1
Q3 is the right most edge of the box which is 45
Q1 is the left most edge of the box which is 25
IQR = Q3 - Q1 = 45 - 25 = 20
Side Note: The median is not 45. The median is actually 40 since this is the middle line of the box, which is in between 35 and 45
Lets write as an equation the info provided in the problem:
original area = 200*300 = 60000 squared meters
Adding x meters to the length is: 300 + x
Adding x meters to the width is: 200 + x
If the area doubles in size we have: 2*<span>60000
Now writing as a single equation all info:
(300 + x)(200 + x) = 120000
We have to make the operations and solve:
60000 + 300x + 200x + x^2 = </span><span>120000
x^2 + 500x - 60000 = 0
This is a squared trinomial, to solve it we need two numbers that subtracted give us 500 and multiplied -60000:
(x + 600)(x -100) = 0
So there are two solutions, x = -600 and x = 100, we choose the positive one:
x = 100
thererefore the value of x is 100 meters</span>
Answer:
im on the same one if i get it right i will comment and tell u k?
Step-by-step explanation:
kk
Answer:1/3 i dont know if this is right i just kindly copied the guy on top
Step-by-step explanation:
