3x+6-2 = 6x-(7/2*9/0)

Mathematics

2 answers:

damaskus [11]2 years ago

8 0

Answer: No Solution

Why?

Any number divided by 0 is not defined, but we are given 9/0 in the question. Hence we cannot solve the equation for the value of ‘x’.

kvv77 [185]2 years ago

5 0

$3x+6-2 = 6x-( \frac{7}{2} \times \frac{9}{0} ) \\ \\ 3x + 4 = 6x - \frac{63}{0} \\ \\ 3x + 4 = 6x - 0 \\ \\ 4 + 0 = 6x - 3x \\ \\ 3x = 4 \\ \\ x = \frac{4}{3} .$

The value of x is 4/3 .

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Question 71

yuradex [85]

Answer:

given

p=q^3

p=40

______

q=(p)^1/3

q=(40)^1/3-->q=2(5)^1/3

Now

the value of half of q , (2(5)^1/3)÷(2) ,is 5^1/3.

finally the value of p gonna be

p=q^3

p=(5^1/3) ^ 3

p=5

3 0

3 years ago

Read 2 more answers

(Question 63) I have the answer in my book, but I have no idea how they got it, so any explaination would be super helpful! Than

vitfil [10]

You have to know that the graph of the arctangent function is a flat S-shaped curve that goes through (0, 0) and has asymptotes at ±π/2. The factor of 2 that multiplies it here expands it vertically so the asymptotes are at ±π. The +3 added to the x causes it to be shifted to the left by 3 units.