Answer is 7950,72. You can solve it's task on calculator.
Answer:
See below.
Step-by-step explanation:
Fifth root of 243 = 3,
Suppose r( cos Ф + i sinФ) is the fifth root of 243(cos 240 + i sin 240),
then r^5( cos Ф + i sin Ф )^5 = 243(cos 240 + i sin 240).
Equating equal parts and using de Moivre's theorem:
r^5 =243 and cos 5Ф + i sin 5Ф = cos 240 + i sin 240
r = 3 and 5Ф = 240 +360p so Ф = 48 + 72p
So Ф = 48, 120, 192, 264, 336 for 48 ≤ Ф < 360
So there are 5 distinct solutions given by:
3(cos 48 + i sin 48),
3(cos 120 + i sin 120),
3(cos 192 + i sin 192),
3(cos 264 + i sin 264),
3(cos 336 + i sin 336).. (Answer).
hope it helped. I have solved in the same paper. plz don't mind.
Answer:
Simplify —————
b - a
1.1 Rewrite (b-a) as (-1) • (a-b)
Canceling Out :
1.2 Cancel out (a-b) which now appears on both sides of the fraction line.
Final result :
-1
Step-by-step explanation:
Answer:
The probability that the mean test score is greater than 290
P(X⁻ > 290 ) = 0.0217
Step-by-step explanation:
<u><em>Step(i):</em></u>-
Mean of the Population (μ) = 281
Standard deviation of the Population = 34.4
Let 'X' be a random variable in Normal distribution
Given X = 290

<u><em>Step(ii):-</em></u>
<em> The probability that the mean test score is greater than 290</em>
P(X⁻ > 290 ) = P( Z > 2.027)
= 0.5 - A ( 2.027)
= 0.5 - 0.4783
= 0.0217
The probability that the mean test score is greater than 290
P(X⁻ > 290 ) = 0.0217