The object must move with the speed of
times to approximately seeing that it is contracted to exactly half of its actual length.
<h3>How is this calculated?</h3>
The length contraction experimented by the object as it approaches lightspeed, in meters per second, is described by Lorentz contraction formula:
![\frac{L}{L'} = \sqrt{(1) - (\frac{v}{c})^{2}](https://tex.z-dn.net/?f=%5Cfrac%7BL%7D%7BL%27%7D%20%3D%20%5Csqrt%7B%281%29%20-%20%28%5Cfrac%7Bv%7D%7Bc%7D%29%5E%7B2%7D)
Here, v is the current speed m/s
c is the speed of light in m/s
L' is the length of the object at rest in m
L is the length of the object at the current speed in m
Now we know that
and
then,
![\frac{1}{2} = \sqrt{1 - r^{2} }\\\frac{1}{4} = 1 - r^{2}\\r^{2} = \frac{3}{4}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%20%3D%20%5Csqrt%7B1%20-%20r%5E%7B2%7D%20%7D%5C%5C%5Cfrac%7B1%7D%7B4%7D%20%3D%201%20-%20r%5E%7B2%7D%5C%5Cr%5E%7B2%7D%20%3D%20%5Cfrac%7B3%7D%7B4%7D)
Hence, r = ![\frac{\sqrt{3} }{2}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%7B3%7D%20%7D%7B2%7D)
Therefore, the answer is the object must travel at a speed of
times the lightspeed to be contracted to one-half its proper length.
To know more about the Lorentz contraction formula, visit:
brainly.com/question/17407131
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Answer:
B) wwl, wwll, european union, cold war
Explanation:
Standing to sue is the third one
I think the answer is if it is done 3 times, because that will make sure you're correct.
You fail the class possibly get summer school but wont affect you in anything and depending on the course it is you will probably still graduate<span />