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3 years ago

10

Mandy collected 4 times as many shells as Cameron. Together they collected 40 shells. How many shells did Mandy collect. Write a

n equation and solve

1 answer:

IRINA_888 [86]3 years ago

4 0

10, because 40 divided by 4 is ten

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Last month, a manufacturing company shipped 452 boxes of ball bearings.Each box contains 48 balls bearings. How many ball bearin

Arturiano [62]

Answer: the company shipped 21,696 ball bearings.

Step-by-step explanation:

Each box contains 48 balls bearings and the company shipped 452 boxes, so it is a simple multiplication 452 times 48 = 21,696

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3 years ago

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What is the measure in degrees of an angle that is supplementary to a 74° angle?

neonofarm [45]

Answer:

106°

Step-by-step explanation:

Supplementary angles total 180°, so the one supplementary to 74° is ...

180° -74° = 106°

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2 years ago

What is -12x-17=-125

xxMikexx [17]

Answer:

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Step-by-step explanation:

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2 years ago

Jim spent 3/8 of his money on eggs. he spent 2/5 of the rest of his money on butter. he had $6.72 left. how much money did him s

anastassius [24]

First make the denominator equal for both fractions.
The LCM of 8 and 5 is 40, so 40 will be the common denominator.
3/8=15/40 and 2/5=16/40
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He has 9/40 of his money left, which means 9/40 of the total money=$6.72
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3 0

2 years ago

Michelle's father deposited $1,000 into a savings account when she was born. The annual interest rate is

prohojiy [21]

Answer:

Michelle's age = 16

Step-by-step explanation:

As we know,

Amount = $P (1 + r)^{t}$ where

P = Principal amount

r = rate of interest

t = time

Given ,

P = $1000

r = 4.5 % = $\frac{4.5}{100} = 0.045$

Now,

Given that Amount reaches more than $2000

⇒ $P (1 + r)^{t}$ > 2000

⇒ $1000(1 + 0.045)^{t}$ > 2000

⇒ $(1.045)^{t}$ > 2

Now,

we put the value of t from 0 , 1, 2, ..... untill the above equation does not satisfy

Now,

for t = 0

$(1.045)^{0} = 1 \ngeq 2$

for t = 1

$(1.045)^{1} = 1.045 \ngeq 2$

for t = 2

$(1.045)^{2} = 1.092 \ngeq 2$

for t = 3

$(1.045)^{3} = 1.14 \ngeq 2$

for t = 4

$(1.045)^{4} = 1.19 \ngeq 2$

for t = 5

$(1.045)^{5} = 1.25 \ngeq 2$

for t = 6

$(1.045)^{6} = 1.30 \ngeq 2$

for t = 7

$(1.045)^{7} = 1.36 \ngeq 2$

for t = 8

$(1.045)^{8} = 1.42 \ngeq 2$

for t = 9

$(1.045)^{9} = 1.48 \ngeq 2$

for t = 10

$(1.045)^{10} = 1.55 \ngeq 2$

for t = 11

$(1.045)^{11} = 1.62 \ngeq 2$

for t = 12

$(1.045)^{12} = 1.69 \ngeq 2$

for t = 13

$(1.045)^{13} = 1.77 \ngeq 2$

for t = 14

$(1.045)^{14} = 1.85 \ngeq 2$

for t = 15

$(1.045)^{15} = 1.93 \ngeq 2$

for t = 16

$(1.045)^{16} = 2.02 > 2$

It satisfies at t= 16

∴ we get

Michelle's age = 16

4 0

2 years ago