Assume:
Size of sides = x m
Depth of the pool = y m
Therefore, surface area = x^2+4xy =10 m^2
Then, y = (10-x^2)/(4x)
Now,
Volume (V) = x^2*y = x^2*y =x^2(10-x^2)/4x = (10x-x^3)/4 = 1/4(10x-x^3)
For maximum volume, first derivative of volume function is equal to zero.
That is,
dV/dx =0 = 1/4(10-3x^2)
Then,
1/4(10-3x^2) = 0
10-3x^2 = 0
3x^2=10
x= sqrt (10/3) = 1.826 m
And
y= (10-1.826^2)/(4*1.826) = 0.913 m
Therefore,
V= 1.826^2*0.913 = 3.044 m^3
Answer:
The real distance would be 16
Step-by-step explanation:
If the scale is 1/2, that means each distance on the map is half of what the real distance is. So 8 x 2 =16.
Volume of a cube is edge^3
Let the smaller cube = e^3 = 1e
Larger cube = 4e^3 = 64e
The ratio would be 64:1
The answer will either be E or 38
