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3 years ago

Triangle 2 is a scale drawing of Triangle 1.

Mathematics

1 answer:

kondaur [170]3 years ago

6 0

Answer:

It would be the bottom

Step-by-step explanation:

because of the length of triangle 1

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Ill mark brainlist plss help

mojhsa [17]

Answer:

w=20

Step-by-step explanation:

Solve for w by cross multiplying.

6 0

3 years ago

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What is the equation for the translation of x2 + y2 = 16 seven units to the right and five units up?

asambeis [7]

Answer:

(x − 7)2 + (y − 5)2 = 16

Step-by-step explanation:

The given circle has equation

$\sf \: x^2+y^2=16x$

The equation of a circle with center (h,k) and radius r units is

$\sf(x-h)^2+(y-k)^2=r^2(x−h)$

$\sf(x-7)^2+(y-5)^2=4^2(x−7)$

$\sf(x-7)^2+(y-5)^2=16(x−7)$

This is the equation that has its center at the origin with radius 4 units.

When this circle is translated seven units to the right and five units up, then the center of the circle will now be at (7,5).

6 0

2 years ago

Twice the product of 3and a number exceeds the sum of the number and 80 by 10.what is the number?

Hatshy [7]

First, create an equation with the criteria given.

If we let x be your number,
$2(3x) = 80 + x + 10$
( $2(3x)$ is twice the product of 3 and x, and if it exceeds $x+80$ by 10, then we add 10 to $x+80$ to make the two sides of the equation equal.)

Now, solve for $x$ .

$6x=90+x \\ 5x=90 \\ x=18$

6 0

3 years ago

What is 25/6 times 2

Darya [45]

25/6 converts to 4 1/6 so
4 1/6 x 2 = 8 1/3
8 1/3 is your answer :)

6 0

3 years ago

Read 2 more answers

Figure ABCD is reflected across the x-axis. What are the coordinates of A' , B' , C' , and D' ? Enter your answer in each box.

stealth61 [152]

Answer:

The coordinates of ABCD after the reflection across the x-axis would become:

A'(2, -3)

B'(5, -5)

C'(7, -3)

D'(5, -2)

Step-by-step explanation:

The rule of reflection implies that when we reflect a point, let say P(x, y), is reflected across the x-axis:

x-coordinate of the point does not change, but

y-coordinate of the point changes its sign

In other words:

The point P(x, y) after reflection across x-axis would be P'(x, -y)

P(x, y) → P'(x, -y)

Given the diagram, the points of the figure ABCD after the reflection across the x-axis would be as follows:

P(x, y) → P'(x, -y)

A(2, 3) → A'(2, -3)

B(5, 5) → B'(5, -5)

C(7, 3) → C'(7, -3)

D(5, 2) → D'(5, -2)

Therefore, the coordinates of ABCD after the reflection across the x-axis would become:

A'(2, -3)

B'(5, -5)

C'(7, -3)

D'(5, -2)

8 0

3 years ago