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Maru [420]
3 years ago
5

Christina is making a necklace using beads. She has 20 red, 14 blue, 10 purple, 28 green, and 8 yellow beads. She randomly choos

es a bead to start the necklace. What is the probability of Christina choosing a bead that is not green?
Mathematics
2 answers:
astra-53 [7]3 years ago
8 0

Answer: 13/20

Step-by-step explanation:

Total number of beads: 20+14+10+28+8=80

Green beads out of the total 80: 28

Non-green beads out of the total 80: 80-28=52

The probability of Christina choosing a bead that is not green is the number if non-green beads divided by the total number of beads, so 52/80, which simplifies to 13/20

Margaret [11]3 years ago
3 0

Answer:

52/70

Step-by-step explanation:

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26. Students who take a statistics course are given a pre-test on the concepts and skills for the first chapter of a statistics
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The test statistic value lies to the right of the critical value. So we have sufficient evidence to reject the null hypothesis.

<h3>What are null hypotheses and alternative hypotheses?</h3>

In null hypotheses, there is no relationship between the two phenomenons under the assumption or it is not associated with the group. And in alternative hypotheses, there is a relationship between the two chosen unknowns.

Students who take a statistics course are given a pre-test on the concepts and skills for the first chapter of a statistics course.

Then they are given a post-test once the professor has concluded lecturing on the material.

Pre-test and post-test scores for 4 students in an elementary statistics class are given below.

Then we have

\mu _d = \mu _{post} - \mu _{pre}

Then the null hypotheses and alternative hypotheses will be

H₀: \mu _d = 0

Hₐ: \mu _d > 0

Then the test statistic will be

\rm \overline{x} _d = \dfrac{\Sigma x_d}{n} = \dfrac{15+12+10+1}{4}\\\\\overline{x} _d = 9.5

Then

\rm S_d = 6.02

The test statistic value is given by

\rm t = \dfrac{\overline{x} _d }{\dfrac{S_d}{\sqrtn}} \\\\t = \dfrac{9.5}{\dfrac{6.02}{\sqrt4}}\\\\t = 3.16

Since this is a right-tailed test, so the critical value is given by

\rm t_{n-1}(\alpha ) = t_3 (0.05) = 2.353

Since the test statistic value lies to the right of the critical value. So we have sufficient evidence to reject the null hypothesis.

Hence, we can conclude that \mu _d > 0 that is test scores have improved.

More about the null hypotheses and alternative hypotheses link is given below.

brainly.com/question/9504281

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2 years ago
Given that f(x) = x^2 - 11x + 18 and g(x) = x-9, find f(x) + g(x)
liberstina [14]

Answer:

f(x) + g(x) = x² - 10x + 9

General Formulas and Concepts:

<u>Algebra I</u>

  • Combining Like Terms

Step-by-step explanation:

<u>Step 1: Define</u>

f(x) = x² - 11x + 18

g(x) = x - 9

<u>Step 2: Find f(x) + g(x)</u>

  1. Substitute:                              f(x) + g(x) = x² - 11x + 18 + x - 9
  2. Combine like terms (x):          f(x) + g(x) = x² - 10x + 9

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Step-by-step explanation:

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And then, find the distance.

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anyanavicka [17]

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Solving the first of these relations for y, we have

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Then the first term of the expansion, x², will be b².

The missing term is b².

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