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3 years ago

What is the result when we simplify the expression

Mathematics

2 answers:

Ostrovityanka [42]3 years ago

7 0

Answer:

Step-by-step explanation:

Here you go mate

Step 1

(1+1x)(1-2x+1)(1+2x-1) Equation/Question

Step 2

(1+1x)(1-2x+1)(1+2x-1) Remove parenthesis

-2x^2+2-4x^3+4x+2x^2-2

Step 3

-2x^2+2-4x^3+4x+2x^2-2 Simplify

-4x^3+4x

Answer

-4x^3+4x

Hope this helps

Julli [10]3 years ago

6 0

Answer:

2x(1+x)(-2x+2)

Step-by-step explanation:

(1+x)(1-2x+1)(1+2x-1)

(1+x)(-2x+2)(1+2x-1)

(1+x)(-2x+2)*2x

2x(1+x)(-2x+2)

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Which angle is a horizontal translation of the first angle?

grin007 [14]

Step-by-step explanation:

B becuase it keeps the same orientation and have the same distance from each point and they both produce rigid motion.

A is a reflection.

C is a dilation.

D is a rotation.

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3 years ago

Which of the following decimal numbers are examples of terminating decimals?

andrew11 [14]

answer:

the answer to the question is c) 14.1

5 0

3 years ago

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2) Dada a equação x2 – 4x – 12, faça o que se pede.

alexandr1967 [171]

Answer:

a) x1 = 6 and x2 = -2

b) -2

Step-by-step explanation:

To find the roots of the quadratic equation, we can use the Bhaskara's formula:

Delta = b^2 - 4ac

Delta = (-4)^2 - 4*1*(-12) = 64

sqrt(Delta) = 8

x1 = (-b + sqrt(Delta)) / 2a

x1 = (4 + 8) / 2

x1 = 6

x2 = (-b - sqrt(Delta)) / 2a

x2 = (4 - 8) / 2

x2 = -2

The roots are 6 and -2, so the smaller root is -2

4 0

3 years ago

What is the probability that a random person who tests positive for a certain blood disease actually has the disease, if we know

xeze [42]

Answer:

Step-by-step explanation:

Hello!

Any medical test used to detect certain sicknesses have several probabilities associated with their results.

Positive (test is +) ⇒ P(+)

True positive (test is + and the patient is sick) ⇒ P(+ ∩ S)

False-positive (test is + but the patient is healthy) ⇒P(+ ∩ H)

Negative (test is -) ⇒ P(-)

True negative (test is - and the patient is healthy) ⇒ P(- ∩ H)

False-negative (test is - but the patient is sick) ⇒ P(- ∩ S)

The sensibility of the test is defined as the capacity of the test to detect the sickness in sick patients (true positive rate).

⇒ P(+/S) = P(+ ∩ S)

P(S)

The specificity of the test is the capacity of the test to have a negative result when the patients are truly healthy (true negative rate)

⇒ P(-/H) = P(- ∩ H)

P(H)

For this particular blood disease the following probabilities are known:

1% of the population has the disease: P(S)= 0.01

95% of those who are sick, test positive for it: P(+/S)= 0.95 (sensibility of the test)

2% of those who don't have the disease, test positive for it: P(+/H)= 0.02

The probability of a person having the blood sickness given that the test was positive is:

P(S/+)= P(+ ∩ S)

P(+)

The first step you need to calculate the intersection between both events + and S, for that you will use the information about the sickness prevalence in the population and the sensibility of the test:

P(+/S) = P(+ ∩ S)

P(S)

P(+/S)* P(S) = P(+ ∩ S)

P(+ ∩ S) = 0.95*0.01= 0.0095

The second step is to calculate the probability of the test being positive:

P(+)= P(+ ∩ S) + P(+ ∩ H)

Now we know that 1% of the population has the blood sickness, wich means that 99% of the population doesn't have it, symbolically: P(H)= 0.99

Then you can clear the value of P(+ ∩ H):

P(+/H) = P(+ ∩ H)

P(H)

P(+/H)*P(H) = P(+ ∩ H)

P(+ ∩ H) = 0.02*0.99= 0.0198

Next you can calculate P(+):

P(+)= P(+ ∩ S) + P(+ ∩ H)= 0.0095 + 0.0198= 0.0293

Now you can calculate the asked probability:

P(S/+)= P(+ ∩ S) = 0.0095 = 0.32

P(+) 0.0293

I hope it helps!

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3 years ago

Iodine-125 has a half-life of about 60 days.

andreyandreev [35.5K]

Since it has a half life of 60 days, this means that every 60 days it multiplies by 0.5. Since it asks for 300 days, your equation is 500*(0.5)^5, which is 15.625 mg left after 300 days.

4 0

4 years ago

Read 2 more answers