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Liula [17]
1 year ago
14

In the inequality 6a+4b>10, what could be the possible value of a if b=2?

Mathematics
1 answer:
Arlecino [84]1 year ago
3 0

We are given the following inequality:

6a+4b>10

If we replace b = 2, we get:

\begin{gathered} 6a+4(2)>10 \\ 6a+8>10 \end{gathered}

Now we solve for "a" first by subtracting 8 on both sides:

\begin{gathered} 6a+8-8>10-8 \\ 6a>2 \end{gathered}

Now we divide both sides by 6

\frac{6a}{6}>\frac{2}{6}

Simplifying:

a>\frac{1}{3}

Therefore, for b = 2, the possible values of "a" are those that are greater than 1/3

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Answer:

y = 30

<u>Skills needed: Angle Geometry</u>

Step-by-step explanation:

1) First, let's see what we should know prior to solving.

---> We have to find the value of y, and looking at that diagram, we have to create an equation.

---> The angle measure of a straight line is 180 degrees, otherwise known as a straight angle (a straight angle is 180 degrees).

---> When you add 3y+3y, you can set that sum equal to 180. This is because the two angles marked 3y added together make a straight line, which is a straight angle.

(Note: In geometry, ONE OF THE THINGS WE CAN ASSUME is that there is a straight line there.)

-------------------------------------------------------------------------------------------------------------

2) Now, the equation would be:

3y+3y=180

6y=180 --> Combining 3y and 3y (3+3 = 6)

y = 180\div6 --> Dividing by 6 on both sides, to get y by itself.

y=30 ---> 180 \div 6 is 30, so y is equal to 30.

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y=30

6 0
2 years ago
Help me on this one please
Troyanec [42]
The answer is 35.

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3 years ago
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