2 years ago

Find x this is a secant secant circle

Advanced Placement (AP)

1 answer:

Serhud [2]2 years ago

8 0

Answer:

x = 11

Explanation:

The measure of the angle formed outside a circle when two secants intercepts = ½(the difference of the intercepted arcs)

Therefore:

5x - 10 = ½(13x + 7 - 60)

Multiply both sides by 2

2(5x - 10) = 13x + 7 - 60

10x - 20 = 13x - 53

Collect like terms

10x - 13x = 20 - 53

-3x = -33

Divide both sides by -3

-3x/-3 = -33/-3

x = 11

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Particle x moves along the positive x-axis so that its position at time t ~ 0 is given by x(t) = 5t 3 - 9t 2 + 7. at what time t

Arada [10]

Answer: 1.2 seconds

Explanation:

$At the farthest point the velocity of particle will be zero. \ Differentiating the given equation of position and equating it with zero:$$\begin{aligned}x(t) &=5 t^{3}-9 t^{2}+7 \\x^{\prime}(t) &=15 t^{2}-18 t \\0 &=15 t^{2}-18 t \\t(15 t-18) &=0 \\t &=0 \\t &=\frac{18}{15}=1.2 \mathrm{~s}\end{aligned}$

$$$Thus, at $t=1.2 \mathrm{~s}$ particle will be at the farthest point. \\\\\underline{Justification:}\\The particle moves towards the left from $t \in[0,1.2)$. After that particle keeps moving in the positive x-direction.$