Question

Write an equation in slope-intercept form of the line that passes through (-1, 4) and (0, 2).

Answer 1

Answer:

$y=-2x+2$

Step-by-step explanation:

Hi there!

Slope-intercept form: $y=mx+b$ where m is the slope and b is the y-intercept (the value of y when the line crosses the y-axis)

1) Determine the slope

$m=\frac{y_2-y_1}{x_2-x_1}$ where the two given points are $(x_1,y_1)$ and $(x_2,y_2)$

Plug in the given points (-1, 4) and (0, 2)

$=\frac{2-4}{0-(-1)}\\=\frac{-2}{0+1}\\=\frac{-2}{1}\\= -2$

Therefore, the slope of the line is -2. Plug this into $y=mx+b$:

$y=-2x+b$

2) Determine the y-intercept

$y=-2x+b$

Recall that the y-intercept is the value of y when the line crosses the y-axis, meaning that the y-intercept occurs when x is equal to 0.

One of the given points is (0,2). Notice how y=2 when x=0. Therefore, the y-intercept of the line is 2.

Plug this back into the equation:

$y=-2x+2$

I hope this helps!