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vovangra [49]
3 years ago
6

Write an equation in slope-intercept form of the line that passes through (-1, 4) and (0, 2).

Mathematics
1 answer:
arsen [322]3 years ago
6 0

Answer:

y=-2x+2

Step-by-step explanation:

Hi there!

Slope-intercept form: y=mx+b where m is the slope and b is the y-intercept (the value of y when the line crosses the y-axis)

<u>1) Determine the slope</u>

m=\frac{y_2-y_1}{x_2-x_1} where the two given points are (x_1,y_1) and (x_2,y_2)

Plug in the given points (-1, 4) and (0, 2)

=\frac{2-4}{0-(-1)}\\=\frac{-2}{0+1}\\=\frac{-2}{1}\\= -2

Therefore, the slope of the line is -2. Plug this into y=mx+b:

y=-2x+b

<u>2) Determine the y-intercept</u>

y=-2x+b

Recall that the y-intercept is the value of y when the line crosses the y-axis, meaning that the y-intercept occurs when x is equal to 0.

One of the given points is (0,2). Notice how y=2 when x=0. Therefore, the y-intercept of the line is 2.

Plug this back into the equation:

y=-2x+2

I hope this helps!

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4.06 Question 9
Jlenok [28]

Answer: B. Graph of 2 lines that intersect at one point. Both lines are solid. One line passes through (-2,2) and (0,3) and is shaded below the line.

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2 < = 1/2(-2) + 3                        3 < = 1/2(0) + 3

2 < = -1 + 3                                3 < = 0 + 3

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The other line passes through points (0,1) and (1,-2) and is shaded above the line.

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