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sesenic [268]
3 years ago
12

Joe and Sally have $89.74 combined. They each had the same amount. What was that amount?

Mathematics
2 answers:
astra-53 [7]3 years ago
8 0

Answer:

44.87

Step-by-step explanation:

Illusion [34]3 years ago
3 0

Answer:

179.48

Step-by-step explanation:

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What is the value of the expression? –13.7+(–5+2.7)
Olegator [25]
-13.7 + (-5 + 2.7)

First, simplify -5 + 2.7 to -2.3 / Your problem should look like: -13.7 + -2.3
Second, simplify to get rid of the addition. / Your problem should look like: -13.7 - 2.3
Third, subtract. / Your problem should look like: -16

Answer: -16 (B)

5 0
3 years ago
Read 2 more answers
5. write an equation for the table of values. explain how you got your answer
Aneli [31]

Answer:

You forgot to put the table

Step-by-step explanation:

8 0
3 years ago
If tanA = 1/2 then evaluate cos A/sinA +sinA /1+cosA​
Deffense [45]

Answer:

√5.

Step-by-step explanation:

Tan A = 1/2 means that the right triangle containing angle A has legs of length 1 and 2 units. So the hypotenuse  = √(1^2 + 2^2) = √5  (using the Pythagoras theorem). The side opposite to < A = 1 unit and the adjacent side = 2 (as tan = opposite / adjacent).

so cos A =  adjacent / hypotenuse =   2/√5.

and sin A = opposite / hypotenuse = 1 / √5

cos A / sin A = 2/√5 /  1/ √5 =  2.

sin A / (1 + cos A) =  1/√5 (1 + 2/ √5)

=  1 / √5 ( (√5 + 2) /√5)

= 1 / (√5 + 2)

So the answer is:

2  +   1 /(√5 + 2).

We can simplify it further by multiplying top and bottom of the fraction by the complement of √5 + 2 which is √5 - 2.

2 + 1 / (√5 + 2)

= 2(√5 + 2) + 1 / (√5 + 2 )

= { 2(√5 + 2) + 1 } /  (√5 + 2)

Multiplying this by  √5 - 2 / √5 - 2 we get:

(2(5 - 4) + √5 - 2) /  (5 -4)

=  2 + √5 - 2 / 1

= √5.

3 0
3 years ago
In the last school election, 88% of the student body voted. If the school has an enrollment of 350 students, how many students v
Brums [2.3K]
88% = 88/100 = 22/25

22/25 x 350 = 7700/25 = 308

Therefore 308 students voted
7 0
3 years ago
Read 2 more answers
Carry out three steps of the Bisection Method for f(x)=3x−x4 as follows: (a) Show that f(x) has a zero in [1,2]. (b) Determine w
ELEN [110]

Answer:

a) There's a zero between [1,2]

b) There's a zero between [1.5,2]

c) There's a zero between  [1.5,1.75].

Step-by-step explanation:

We have f(x)=3^x-x^4

A)We need to show that f(x) has a zero in the interval [1, 2]. We have to see if the function f is continuous with f(1) and f(2).

f(x)=3^x-x^4\\\\f(1)=3^1-(1)^4=3-1=2\\\\f(2)=3^2-(2)^4=9-16=(-7)

We can see that f(1) and f(2) have opposite signs. And f(1)>f(2) and the function is continuous, this means that exists a real number c between the interval [1,2] where f(c)=0.

B)We have to repeat the same steps of A)

For the subinterval [1,1.5]:

f(x)=3^x-x^4\\\\f(1)=3^1-(1)^4=3-1=2\\\\f(1.5)=3^1^.^5-(1.5)^4=5.19-5.06=0.13

f(1) and f(1.5) have the same signs, this means there's no zero in the subinterval [1,1.5].

For the subinterval [1.5,2]:

f(x)=3^x-x^4\\\\f(1.5)=3^1^.^5-(1.5)^4=5.19-5.06=0.13\\\\f(2)=3^2-(2)^4=9-16=(-7)

f(1.5) and f(2) have opposite signs, this means there's a zero between the subinterval [1.5,2].

C)We have to repeat the same steps of A)

For the subinterval [1,1.25]:

f(x)=3^x-x^4\\\\f(1)=3^1-(1)^4=3-1=2\\\\f(1.25)=3^1^.^2^5-(1.25)^4=3.94-2.44=1.5

f(1) and f(1.25) have the same signs, this means there's no zero in the subinterval [1,1.25].

For the subinterval [1.25,1.5]:

f(x)=3^x-x^4\\\\f(1.25)=3^1^.^2^5-(1.25)^4=3.94-2.44=1.5\\\\f(1.5)=3^1^.^5-(1.5)^4=5.19-5.06=0.13

f(1.25) and f(1.5) have the same signs, this means there's no zero in the subinterval [1.25,1.5].

For the subinterval [1.5,1.75]:

f(x)=3^x-x^4\\\\f(1.5)=3^1^.^5-(1.5)^4=5.19-5.06=0.13\\\\f(1.75)=3^1^.^7^5-(1.75)^4=6.83-9.37=(-2.54)

f(1.5) and f(1.75) have opposite signs, this means there's a zero between the subinterval [1.5,1.75].

For the subinterval [1.75,2]:

f(x)=3^x-x^4\\\\f(1.75)=3^1^.^7^5-(1.75)^4=6.83-9.37=(-2.54)\\\\f(2)=3^2-(2)^4=9-16=(-7)

f(1.75) and f(2) have the same signs, this means there isn't a zero between the subinterval [1.75,2].

The graph of the function shows that the answers are correct.

6 0
3 years ago
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